In the circuit shown below, the network $\mathrm{N}$ is described by the following $Y$ matrix:
$Y=\left[\begin{array}{cc}0.1 \mathrm{~S} & -0.01 \mathrm{~S} \\ 0.01 \mathrm{~S} & 0.1 \mathrm{~S}\end{array}\right]$. The voltage gain $\dfrac{V_2}{V_1}$ is
- $1 / 90$
- $ – 1 / 90$
- $ – 1 / 99$
- $ – 1 / 11$