1 votes 1 votes In the circuit shown below, the Norton equivalent current in amperes with respect to the terminals $\mathrm{P}$ and $\mathrm{Q}$ is $6.4-\mathrm{j} 4.8$ $6.56-\mathrm{j} 7.87$ $10+\mathrm{j} 0$ $16+\mathrm{j} 0$ Others gate2011-ec + – admin asked Sep 3, 2022 • edited Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 149 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
