3 views

In the circuit shown below, the Norton equivalent current in amperes with respect to the terminals $\mathrm{P}$ and $\mathrm{Q}$ is

1. $6.4-\mathrm{j} 4.8$
2. $6.56-\mathrm{j} 7.87$
3. $10+\mathrm{j} 0$
4. $16+\mathrm{j} 0$