0 0 votes If $G(f)$ represents the Fourier transform of a signal $g$ (t) which is real and odd symmetric in time, then $\mathrm{G}(f)$ is complex $G(f)$ is imaginary $\mathrm{G}(f)$ is real $\mathrm{G}(f)$ is real and non-negative. Continuous-time Signals gate1992-ec signals-and-systems fourier-transform continuous-time-signals + – admin 239 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.