1 votes 1 votes The current $\mathrm{I}$ in the circuit shown is $\text{-j1 A}$ $\text{j1 A}$ $0 \mathrm{~A}$ $20 \mathrm{~A}$ Others gate2010-ec + – admin asked Sep 15, 2022 • edited Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 37 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.