In the Digital-to-Analog converter circuit shown in the figure below, $V_{R}=10 \mathrm{~V}$ and $\mathrm{R}=10 \; \mathrm{k} \Omega$.
The current $i$ is
- $31.25 \; \mu \mathrm{A}$
- $62.5 \; \mu \mathrm{A}$
- $125 \; \mu \mathrm{A}$
- $250 \; \mu \mathrm{A}$