7 views

0 votes

A medium is divided into regions I and II about $x=0$ plane, as shown in the figure below. An electromagnetic wave with electric field $\mathrm{E}_{1}=4 \hat{a}_{x}+3 \hat{a}_{y}+5 \hat{a}_{z}$ is incident normally on the interface from region-I. The electric field $E_{2}$ in region-II at the interface is

- $\mathrm{E}_{2}=\mathrm{E}_{1}$
- $4 \hat{a}_{x}+0.75 \hat{a}_{y}-1.25 \hat{a}_{z}$
- $3 \hat{a}_{x}+3 \hat{a}_{y}+5 \hat{a}_{z}$
- $-3 \hat{a}_{x}+3 \hat{a}_{y}+5 \hat{a}$