1 1 vote Let $x(t) \longleftrightarrow \mathrm{X}(j \omega)$ be Fourier Transform pair. The Fourier Transform of the signal $x(5 t-3)$ in terms of $X(j \omega)$ is given as $\frac{1}{5} e^ – \frac{j 3\omega }{5} \times\left(\frac{j \omega}{5}\right)$ $\frac{1}{5} e^\frac{j 3 \omega}{5} \times \left(\frac{j \omega}{5}\right)$ $\frac{1}{5} e^{-j 3 \omega} \times \left(\frac{j \omega }{5}\right)$ $\frac{1}{5} e^{j 3 \omega} \times\left(\frac{j \omega}{5}\right)$ Continuous-time Signals gate2006-ec continuous-time-signals signals-and-systems fourier-transform + – admin 264 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
