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Let $x(t) \longleftrightarrow \mathrm{X}(j \omega)$ be Fourier Transform pair. The Fourier Transform of the signal $x(5 t-3)$ in terms of $X(j \omega)$ is given as

- $\frac{1}{5} e^ – \frac{j 3 m}{5} \times\left(\frac{j \omega}{5}\right)$
- $\frac{1}{5} e^\frac{j 3 m}{5} \times \left(\frac{j \omega}{5}\right)$
- $\frac{1}{5} e^{j 3 m} \times \left(\frac{j \omega s}{5}\right)$
- $\frac{1}{5} e^\frac{j 3 m}{5} \times\left(\frac{j \omega}{5}\right)$