0 votes 0 votes The value of the integral $\text{I}=\frac{1}{\sqrt{2 \pi}} \int_{0}^{\infty} \exp \left(-\frac{x^{2}}{8}\right)$ $d x$ is $1$ $\pi$ $2$ $2 \pi$ Others gate2005-ec + – admin asked Sep 22, 2022 • edited Nov 30, 2023 by makhdoom ghaya admin 46.4k points 256 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.