0 0 votes The value of the integral $\text{I}=\frac{1}{\sqrt{2 \pi}} \int_{0}^{\infty} \exp \left(-\frac{x^{2}}{8}\right)$ $d x$ is $1$ $\pi$ $2$ $2 \pi$ Probability and Statistics gate2005-ec calculus numerical-answers + – admin 650 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
