0 0 votes Let $x(t)$ and $y(t)$ (with Fourier transforms $X(f)$ and $Y(f)$ respectively) be related as shown in the given figure. Then $Y(f)$ is $-\frac{1}{2} X(f / 2) e^{-j 2 \pi f}$ $-\frac{1}{2} X(f / 2) e^{j 2 \pi f}$ $-X(f / 2) e^{j 2 \pi f}$ $-\mathrm{X}(f / 2) e^{-j2 \pi f}$ Continuous-time Signals gate2004-ec signals-and-systems fourier-transform continuous-time-signals + – admin 179 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
