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Let $x(t)$ and $y(t)$ (with Fourier transforms $X(f)$ and $Y(f)$ respectively) be related as shown in the given figure.

Then $Y(f)$ is

  1. $-\frac{1}{2} X(f / 2) e^{-j 2 \pi f}$
  2. $-\frac{1}{2} X(f / 2) e^{j 2 \pi f}$
  3. $-X(f / 2) e^{j 2 \pi f}$
  4. $-\mathrm{X}(f / 2) e^{-j2 \pi f}$
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