Let $x(t)$ and $y(t)$ (with Fourier transforms $X(f)$ and $Y(f)$ respectively) be related as shown in the given figure.
Then $Y(f)$ is
- $-\frac{1}{2} X(f / 2) e^{-j 2 \pi f}$
- $-\frac{1}{2} X(f / 2) e^{j 2 \pi f}$
- $-X(f / 2) e^{j 2 \pi f}$
- $-\mathrm{X}(f / 2) e^{-j2 \pi f}$