0 0 votes In a full-wave rectifier using two ideal diodes, $V_{d i}$ and $V_{i d}$ are the $d c$ and peak values of the voltage respectively across a resistive load. If PIV is the peak inverse voltage of the diode, then the appropriate relationships for this rectifier are $\mathrm{V}_{\text {dc }}=\frac{\mathrm{V}_{m}}{\pi}, \mathrm{PIV}=2 \mathrm{~V}_{\mathrm{dc}}$ $\mathrm{V}_{d \mathrm{dc}}=2 \frac{\mathrm{V}_{\text {m }}}{\pi}, \mathrm{PIV}=2 \mathrm{~V}_{\mathrm{dc}}$ $\mathrm{V}_{dc}=2 \frac{\mathrm{V}_{m}}{\pi}, \mathrm{PIV}=\mathrm{V}_{\mathrm{dc}}$ $\mathrm{V}_{\text {dc}}=\frac{\mathrm{V}_{\mathrm{m}}}{\pi}, \mathrm{PIV}=\mathrm{V}_{\text {dc}}$ Diode Circuits gate2004-ec diode-circuits circuit-analysis analog-circuits numerical-answers + – admin 436 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.