0 votes 0 votes The PDF of a Gaussian random variable $X$ is given by $\operatorname{Px}(x)=\frac{1}{3 \sqrt{2 \pi}} e^{\frac{-(x-4)^{2}}{18}}$ The probability of the event $\{X=4\}$ is $\frac{1}{2}$ $\frac{1}{3 \sqrt{2 \pi}}$ $0$ $\frac{1}{4}$ Others gate2001-ec + – admin asked Sep 29, 2022 • edited Nov 30, 2023 by makhdoom ghaya admin 46.4k points 83 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.