0 0 votes An amplifier has an open-loop gain of $100$, an input impedance of $1 \; \mathrm{k \Omega}$, and an output impedance of $100 \; \Omega$. A feedback network with a feedback factor of $0.99$ is connected to the amplifier in a voltage series feedback mode. The new input and output impedances, respectively, are $10 \; \Omega$ and $1 \; \Omega$ $10 \; \Omega$ and $10 \; k \Omega$ $100 \; \Omega$ and $1 \; \Omega$ $100 \; k \Omega$ and $1 \; k\Omega$ Op-amp Circuits gate1999-ec circuit-analysis analog-circuits amplifier feedback-systems + – admin 284 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes None of these. Answer is 100k ohm and 1 ohm respectively. factor = 1 + Ab = 1 + (100)(0.99) = 100 For voltage series, Zif = Zi x factor = 1000 x 100 = 100k ohm Zof = Zi / factor = 100 / 100 = 1 ohm shankari29 answered Feb 3 shankari29 comment Share Follow 0 reply Please log in or register to add a comment.