GATE ECE 1999 | Question 1.19

Question

The input to a channel is a bandpass signal. It is obtained by linearly modulating a sinusoidal carrier with a single-tone signal. The output of the channel due to this input is given by
\[
y(t)=(1 / 100) \cos \left(100 t-10^{-6}\right) \cos \left(10^{6} t-1.56\right)
\]
The group delay $\left(t_{g}\right)$ and the phase delay $\left(t_{p}\right)$ in seconds, of the channel are

• A. $t_{g}=10^{-6}, t_{p}=1.56$
• B. $t_{g}=1.56, t_{p}=10^{-6}$
• C. $t_{g}=10^{8}, t_{p}=1.56 \times 10^{-6}$
• D. $t_{g}=10^{8}, t_{p}=1.56$