2 2 votes A continuous time signal $x(t)=2 \cos (8 \pi t+\pi / 3)$ is sampled at a rate of $15 \mathrm{~Hz}$. The sampled signal $x_{s}(t)$ when passed through an LTI system with impulse response \[ h(t)=\left(\frac{\sin 2 \pi t}{\pi t}\right) \cos (38 \pi t-\pi / 2) \] produces an output $x_{o}(t)$. The expression for $x_{o}(t)$ is $\_\_\_\_\_$. $15 \sin (38 \pi t+\pi / 3)$ $15 \sin (38 \pi t-\pi / 3)$ $15 \cos (38 \pi t-\pi / 6)$ $15 \cos (38 \pi t+\pi / 6)$ Continuous-time Signals gateece-2024 impulse-response continuous-time-signals linear-time-invariant-systems + – admin 905 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes C Saby69 answered Dec 12, 2025 Saby69 comment Share Follow 0 reply Please log in or register to add a comment.