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Recent questions tagged gate1993-ec
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GATE ECE 1993 | Question 4.6
For the amplifier circuit of the figure is the transistor a $\mathrm{B}$ of $800$ . The midband voltage gain $\mathrm{V}^{0} / \mathrm{V}^{1}$, of the circuit will be $0$ $<1$ $\approx 1$ $800$
For the amplifier circuit of the figure is the transistor a $\mathrm{B}$ of $800$ . The midband voltage gain $\mathrm{V}^{0} / \mathrm{V}^{1}$, of the circuit will be$0$$...
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GATE ECE 1993 | Question 4.7
The waveshape of $\mathrm{V}^{0}$ in the figure will be
The waveshape of $\mathrm{V}^{0}$ in the figure will be
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GATE ECE 1993 | Question 4.8
For the logic circuit shown in the figure is the output $Y$ is equal to $\overline{\mathrm{ABC}}$ $\overline{\mathrm{A}}+\overline{\mathrm{B}}+\overline{\mathrm{C}}$ $\overline{\mathrm{AB}}+\overline{\mathrm{BC}}+\overline{\mathrm{A}}+\overline{\mathrm{C}}$
For the logic circuit shown in the figure is the output $Y$ is equal to$\overline{\mathrm{ABC}}$$\overline{\mathrm{A}}+\overline{\mathrm{B}}+\overline{\mathrm{C}}$$\overl...
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GATE ECE 1993 | Question 4.9
In the figure, is in ideal moving iron voltmeter $M$ will read $7.07 \mathrm{~V}$ $12.24 \mathrm{~V}$ $14.14 \mathrm{~V}$ $20.0 \mathrm{~V}$
In the figure, is in ideal moving iron voltmeter $M$ will read$7.07 \mathrm{~V}$$12.24 \mathrm{~V}$$14.14 \mathrm{~V}$$20.0 \mathrm{~V}$
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GATE ECE 1993 | Question 6.1
A network contains linear resistors and ideal voltage sources. If values of all the resistors are doubled, then the voltage across each resistor is halved doubled increased by four times not changed
A network contains linear resistors and ideal voltage sources. If values of all the resistors are doubled, then the voltage across each resistor ishalveddoubledincreased ...
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GATE ECE 1993 | Question 6.2
The two electrical sub network $N^{1}$ and $N^{2}$ are connected through three resistors as shown in the figure. The voltage across $5 \; \mathrm{ohm}$ resistor and $1 \; \mathrm{ohm}$ resistor are given to be $10 \mathrm{~V}$ and $5 \mathrm{~V}$, respectively. ... $-105 \mathrm{~V}$ $+105 \mathrm{~V}$ $-15 \mathrm{~V}$ $+15 \mathrm{~V}$
The two electrical sub network $N^{1}$ and $N^{2}$ are connected through three resistors as shown in the figure. The voltage across $5 \; \mathrm{ohm}$ resistor and $1 \;...
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GATE ECE 1993 | Question 6.3
In the figure is $\mathrm{A}^{1} \mathrm{~A}^{2}$ and $\mathrm{A}^{3}$ are ideal ammeters. If $\mathrm{A}^{1}$ reads $5 \mathrm{A}, \mathrm{~A}^{2}$ reads $12 \mathrm{A}$, then $\mathrm{A}^{3}$ should read. $7 \mathrm{~A}$ $12 \mathrm{~A}$ $13 \mathrm{~A}$ $17 \mathrm{~A}$
In the figure is $\mathrm{A}^{1} \mathrm{~A}^{2}$ and $\mathrm{A}^{3}$ are ideal ammeters. If $\mathrm{A}^{1}$ reads $5 \mathrm{A}, \mathrm{~A}^{2}$ reads $12 \mathrm{A}$...
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GATE ECE 1993 | Question 6.4
If $\tau \mathrm{F}(\mathrm{s})=[f(t)]=\frac{\mathrm{K}}{(\mathrm{s}+1)\left(\mathrm{s}^{2}+4\right)}$ then $\lim _{t \rightarrow \infty} f(t)$ is given by $\mathrm{K} / 4$ zero infinite undefined
If $\tau \mathrm{F}(\mathrm{s})=[f(t)]=\frac{\mathrm{K}}{(\mathrm{s}+1)\left(\mathrm{s}^{2}+4\right)}$ then $\lim _{t \rightarrow \infty} f(t)$ is given by$\mathrm{K} / 4...
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GATE ECE 1993 | Question 6.5
If $s^{3}+3 s^{2}+4 s+A=0$, then all the roots of this equation are in the left half plane provided that $\mathrm{A}>12$ $-3<\mathrm{A}<4$ $0<\mathrm{A}<12$ $5<\mathrm{A}<12$
If $s^{3}+3 s^{2}+4 s+A=0$, then all the roots of this equation are in the left half plane provided that$\mathrm{A}>12$$-3<\mathrm{A}<4$$0<\mathrm{A}<12$$5<\mathrm{A}<12$...
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GATE ECE 1993 | Question 6.7
$\alpha$ - cut off frequency of a bipolar junction transistor increases with the increase in base width increases with the increase in emitter width increases with increase in the collector width increases with decrease in the base width.
$\alpha$ - cut off frequency of a bipolar junction transistorincreases with the increase in base widthincreases with the increase in emitter widthincreases with increase ...
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GATE ECE 1993 | Question 6.8
Negative feedback in amplifiers improves the signal to noise ratio at the input improves the signal to noise ratio at the output does not affect the signal to noise ratio at the output reduces distortion
Negative feedback in amplifiersimproves the signal to noise ratio at the inputimproves the signal to noise ratio at the outputdoes not affect the signal to noise ratio at...
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GATE ECE 1993 | Question 6.9
In a multi-stage $\text{R-C}$ coupled amplifier the coupling capacitor limits the low frequency response limits the high frequency response does not affect the frequency response blocks the $d.c.$ component without affecting the frequency response
In a multi-stage $\text{R-C}$ coupled amplifier the coupling capacitorlimits the low frequency responselimits the high frequency responsedoes not affect the frequency res...
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GATE ECE 1993 | Question 6.10
The bandwidth of an $n$-stage tuned amplifier, with each stage having a band width of $B$, is given by $\mathrm{B} / n$ $\mathrm{B} / \sqrt{n}$ $\mathrm{B} \sqrt{2^{1 / n}-1}$ $\mathrm{B} / \sqrt{2^{1 / n}-1}$
The bandwidth of an $n$-stage tuned amplifier, with each stage having a band width of $B$, is given by$\mathrm{B} / n$$\mathrm{B} / \sqrt{n}$$\mathrm{B} \sqrt{2^{1 / n}-1...
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GATE ECE 1993 | Question 6.11
In a transistor push-pull amplifier there is no $d.c.$ present in the output there is no distortion in the output there are no even harmonics in the output there are no odd harmonics in the output
In a transistor push-pull amplifierthere is no $d.c.$ present in the outputthere is no distortion in the outputthere are no even harmonics in the outputthere are no odd h...
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GATE ECE 1993 | Question 6.12
$2$'s complement representation of a $16$ – bit number (one sign bit and $15$ magnitude bits) is $\text{FFFI}$. Its magnitude in decimal representation is $0$ $1$ $32,767$ $65,535$
$2$'s complement representation of a $16$ – bit number (one sign bit and $15$ magnitude bits) is $\text{FFFI}$. Its magnitude in decimal representation is$0$$1$$32,767$...
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GATE ECE 1993 | Question 6.13
Boolean expression for the output of $\text{XNOR}$ (Equivalent) logic gate with inputs $A$ and $B$ is $\mathrm{A} \overline{\mathrm{B}}+\overline{\mathrm{A}} \mathrm{B}$ $\overline{\mathrm{AB}}+\mathrm{AB}$ $(\overline{\mathrm{A}}+\mathrm{B})(\mathrm{A}+\overline{\mathrm{B}})$ $(\overline{\mathrm{A}}+\overline{\mathrm{B}})(\mathrm{A}+\mathrm{B})$
Boolean expression for the output of $\text{XNOR}$ (Equivalent) logic gate with inputs $A$ and $B$ is$\mathrm{A} \overline{\mathrm{B}}+\overline{\mathrm{A}} \mathrm{B}$$\...
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GATE ECE 1993 | Question 6.14
Consider the circuit shown in the figure is If the diode used here has the V-I characteristic as in the figure is then the output waveform $v^{0}$ is
Consider the circuit shown in the figure is If the diode used here has the V-I characteristic as in the figure is then the output waveform $v^{0}$ is
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GATE ECE 1993 | Question 6.15
A pulse train with a frequency of $1 \; \mathrm{MHz}$ is counted using a modulo $1024$ ripple-counter built with $\text{JK}$ flip flops. For proper operation of the counter, the maximum permissible propagation delay per flip flop stage is $ \dots n \mathrm{Sec}$.
A pulse train with a frequency of $1 \; \mathrm{MHz}$ is counted using a modulo $1024$ ripple-counter built with $\text{JK}$ flip flops. For proper operation of the count...
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GATE ECE 1993 | Question 6.16
In a microprocessor, the register which holds the address of the next instruction to be fetched is Accumulator Program Counter Stack Pointer Instruction Registor
In a microprocessor, the register which holds the address of the next instruction to be fetched isAccumulatorProgram CounterStack PointerInstruction Registor
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GATE ECE 1993 | Question 6.17
In a microcomputer, wait states are used to make the processor wait during a $\text{DMA}$ operation make the processor wait during an interrupt processing make the processor wait during a power shutdown interface slow peripherals to the processor
In a microcomputer, wait states are used tomake the processor wait during a $\text{DMA}$ operationmake the processor wait during an interrupt processingmake the processor...
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GATE ECE 1993 | Question 6.18
The function shown in figure, can represent a probability density function for $\mathrm{A} \dots$
The function shown in figure, can represent a probability density function for $\mathrm{A} \dots$
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GATE ECE 1993 | Question 6.19
Which of the following demodulator(s) can be used for demodulating the signal $x(t)=5(1+2 \cos 2000 \pi t) \cos 2000 \pi t .$ Envelope demodulator Square-law demodulator Synchronous demodulator None of these
Which of the following demodulator(s) can be used for demodulating the signal $x(t)=5(1+2 \cos 2000 \pi t) \cos 2000 \pi t .$Envelope demodulatorSquare-law demodulatorSyn...
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GATE ECE 1993 | Question 6.20
A superheterodyne radio receiver with an intermediate frequency of $455 \; \mathrm{KHz}$ is tuned to a station operating at $1200 \; \mathrm{KHz}$. The associated image frequency is $\dots \text{KHz}$.
A superheterodyne radio receiver with an intermediate frequency of $455 \; \mathrm{KHz}$ is tuned to a station operating at $1200 \; \mathrm{KHz}$. The associated image f...
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GATE ECE 1993 | Question 6.21
Sketch the waveform (with properly markedaxes) at the output of a matched filter matched for a signal $S(t)$, of duration $T$, given by $ S(t)= \begin{cases}\text { A } & \text { for } 0<t<\frac{2}{3} \mathrm{~T} \\ 6.22 & \text { for } \frac{2}{3} \mathrm{~T} \leq t<\mathrm{T}\end{cases} $
Sketch the waveform (with properly markedaxes) at the output of a matched filter matched for a signal $S(t)$, of duration $T$, given by $$ S(t)= \begin{cases}\text { A } ...
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GATE ECE 1993 | Question 6.22
Six independent low pass signals of bandwidth $3\mathrm{W}, \mathrm{W}, \mathrm{W}, 2 \mathrm{W}, 3 \mathrm{W}$, and $2 \mathrm{W} \mathrm{~Hz}$ are to be time-division-multiplexer on a common channel using $\text{PAM}$. To achieve this, the minimum transmission bandwidth of the channel should be $ \dots \mathrm{Hz}$.
Six independent low pass signals of bandwidth $3\mathrm{W}, \mathrm{W}, \mathrm{W}, 2 \mathrm{W}, 3 \mathrm{W}$, and $2 \mathrm{W} \mathrm{~Hz}$ are to be time-division-m...
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GATE ECE 1993 | Question 6.23
A material is described by the following electrical parameters as a frequency of $10 \; \mathrm{GHz}, \sigma=10^{6} \mathrm{mho} / \mathrm{m}, \mu=\mu^{0}$ and $\sigma / \sigma^{0}=10$. The material at this frequency is considered ... {~F} / \mathrm{m}\right)\] a good conductor a good dielectric neither a good conductor, nor a good dielectric a good magnetic material
A material is described by the following electrical parameters as a frequency of $10 \; \mathrm{GHz}, \sigma=10^{6} \mathrm{mho} / \mathrm{m}, \mu=\mu^{0}$ and $\sigma / ...
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GATE ECE 1993 | Question 6.24
Consider a transmission line of characteristic impedance of $50 \; \mathrm{ohm}$. Let it be terminated at one end by $+j \; 50 \; \mathrm{ohm}$. The $\text{VSWR}$ produced by it in the transmission line will be $+1$ $0$ $\infty$ $+j$
Consider a transmission line of characteristic impedance of $50 \; \mathrm{ohm}$. Let it be terminated at one end by $+j \; 50 \; \mathrm{ohm}$. The $\text{VSWR}$ produce...
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GATE ECE 1993 | Question 6.25
A plane wave is incident normally on a perfect conductor as shown in figure. Here $E_{x}^{r}=\mathrm{H}^{\prime}$, and $\overrightarrow{\mathrm{P}}$ are electric field, magnetic field and Poynting vector respectively, for the incident wave. The reflected wave should ... $\overrightarrow{\mathrm{P}}=-\overrightarrow{\mathrm{P}}$ $\mathrm{E}_{x}^{r}=\mathrm{E}_{x}$
A plane wave is incident normally on a perfect conductor as shown in figure. Here $E_{x}^{r}=\mathrm{H}^{\prime}$, and $\overrightarrow{\mathrm{P}}$ are electric field, m...
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