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Recent questions tagged gate1998-ec

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41
GATE ECE 1998 | Question: 1.40
The units of $\frac{q}{k T}$ are $\mathrm{V} $ $\mathrm{V}^{-1}$ $\mathrm{J} $ $\mathrm{J} / \mathrm{K}$
The units of $\frac{q}{k T}$ are$\mathrm{V} $$\mathrm{V}^{-1}$$\mathrm{J} $$\mathrm{J} / \mathrm{K}$
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42
GATE ECE 1998 | Question 2.2
The noise margin of a $\text{TTL}$ gate is about $0.2 \mathrm{~V}$ $0.4 \mathrm{~V}$ $0.6 \mathrm{~V}$ $0.8 \mathrm{~V}$
The noise margin of a $\text{TTL}$ gate is about$0.2 \mathrm{~V}$$0.4 \mathrm{~V}$$0.6 \mathrm{~V}$$0.8 \mathrm{~V}$
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43
GATE ECE 1998 | Question 2.3
In the figure is $A=1$ and $B=1$, the input $B$ is now replaced by a sequence $101010 \ldots$. , the outputs $x$ and $y$ will be fixed at $0$ and $1$, respectively $x=1010 \ldots \ldots$ while $y=0101 \ldots \ldots$ $x=1010 \ldots \ldots$ and $y=1010 \ldots \ldots$. fixed at $1$ and $0$, respectively
In the figure is $A=1$ and $B=1$, the input $B$ is now replaced by a sequence $101010 \ldots$. , the outputs $x$ and $y$ will befixed at $0$ and $1$, respectively$x=1010 ...
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44
GATE ECE 1998 | Question 2.4
An equivalent $2^{\prime} s$ complement representation of the $2$'s complement number $1101$ is $110100$ $001101$ $110111$ $111101$
An equivalent $2^{\prime} s$ complement representation of the $2$'s complement number $1101$ is$110100$$001101$$110111$$111101$
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45
GATE ECE 1998 | Question 2.5
The threshold voltage for each transistor in the figure is $2 \mathrm{V}$. For this circuit to work as an inverter, $V_{i}$ must take the values $-5 \mathrm{~V}$ and $0 \mathrm{~V}$ $-5 \mathrm{~V}$ and $5 \mathrm{~V}$ $-0 \mathrm{~V}$ and $3 \mathrm{~V}$ $3 \mathrm{~V}$ and $5 \mathrm{~V}$
The threshold voltage for each transistor in the figure is $2 \mathrm{V}$. For this circuit to work as an inverter, $V_{i}$ must take the values$-5 \mathrm{~V}$ and $0 \m...
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GATE ECE 1998 | Question 2.6
An $\text{I/O}$ processor control the flow of information between cache memory and $\text{I / O}$ devices main memory and $\text{I / O}$ devices two $\text{I/ O}$ devices cache and main memories
An $\text{I/O}$ processor control the flow of information betweencache memory and $\text{I / O}$ devicesmain memory and $\text{I / O}$ devicestwo $\text{I/ O}$ devicescac...
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GATE ECE 1998 | Question 2.7
Two $2^{\prime}$ 's complement number having sign bits $x$ and $y$ are added and the sign bit of the result is $z$. Then, the occurrence of overflow is indicated by the Boolean function $x y z$ $\bar{x} \bar{y} \bar{z}$ $\bar{x} \bar{y} z+x y \bar{z}$ $x y+y z+z x$
Two $2^{\prime}$ 's complement number having sign bits $x$ and $y$ are added and the sign bit of the result is $z$. Then, the occurrence of overflow is indicated by the B...
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48
GATE ECE 1998 | Question 2.8
The advantage of using a dual slope $\text{ADC}$ in a digital voltmeter is that its conversion time is small its accuracy is high it gives output in $\text{BCD}$ format it does not require a comparator
The advantage of using a dual slope $\text{ADC}$ in a digital voltmeter is thatits conversion time is smallits accuracy is highit gives output in $\text{BCD}$ formatit do...
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49
GATE ECE 1998 | Question 2.9
For the identity $\mathrm{AB}+\overline{\mathrm{A}} C+\mathrm{BC}=\mathrm{AB}+\overline{\mathrm{A}} \mathrm{C}$ ...
For the identity $\mathrm{AB}+\overline{\mathrm{A}} C+\mathrm{BC}=\mathrm{AB}+\overline{\mathrm{A}} \mathrm{C}$, the dual form is$(\mathrm{A}+\mathrm{B})(\overline{\mathr...
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50
GATE ECE 1998 | Question 2.10
An instruction used to set the carry Flag in a computer can be classified as data transfer arithmetic logical program control
An instruction used to set the carry Flag in a computer can be classified asdata transferarithmeticlogicalprogram control
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51
GATE ECE 1998 | Question 2.11
The figure is shows a mod- $\mathrm{K}$ counter, here $\mathrm{K}$ is equal to $1$ $2$ $3$ $4$
The figure is shows a mod- $\mathrm{K}$ counter, here $\mathrm{K}$ is equal to$1$$2$$3$$4$
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GATE ECE 1998 | Question 2.12
The current $I$ through resistance $\mathrm{r}$ in the circuit shown in the figure is $\frac{-\mathrm{V}}{12 \mathrm{R}}$ $\frac{\mathrm{V}}{12 \mathrm{R}}$ $\frac{\text{V}}{6 \text{R}}$ $\frac{\mathrm{V}}{3 \mathrm{~T}}$
The current $I$ through resistance $\mathrm{r}$ in the circuit shown in the figure is $\frac{-\mathrm{V}}{12 \mathrm{R}}$$\frac{\mathrm{V}}{12 \mathrm{R}}$$\frac{\text{V}...
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53
GATE ECE 1998 | Question 2.13
The $K$-map for a Boolean function is shown in the figure is The number of essential prime implicants for this function is $4$ $5$ $6$ $8$
The $K$-map for a Boolean function is shown in the figure is The number of essential prime implicants for this function is$4$$5$$6$$8$
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GATE ECE 1998 | Question 2.14
For small signal $a.c$. operation, a practical forward biased diode can be modelled as a resistance and a capacitance in series an ideal diode and resistance in parallel a resistance and an ideal diode in series a resistance
For small signal $a.c$. operation, a practical forward biased diode can be modelled asa resistance and a capacitance in seriesan ideal diode and resistance in parallela r...
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GATE ECE 1998 | Question 2.15
The amplitude spectrum of a Gaussian pulse is uniform a sine function Gaussian an impulse function
The amplitude spectrum of a Gaussian pulse isuniforma sine functionGaussianan impulse function
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GATE ECE 1998 | Question 2.16
The $\text{ACF}$ of a rectangular pulse of duration $\mathrm{T}$ is a rectangular pulse of duration $\mathrm{T}$ a rectangular pulse of duration $\mathrm{2T}$ a triangular pulse of duration $\text{T}$ a triangular pulse of duration $2 \mathrm{T}$
The $\text{ACF}$ of a rectangular pulse of duration $\mathrm{T}$ isa rectangular pulse of duration $\mathrm{T}$a rectangular pulse of duration $\mathrm{2T}$a triangular p...
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GATE ECE 1998 | Question 2.17
The image channel selectivity of superheterodyne receiver depends upon $\text{IF}$ amplifiers only $\text{RF}$ and $\text{IF}$ amplifiers only Preselector, $\text{RF}$ and $\text{IF}$ amplifiers Preselector, and $\text{RF}$ amplifiers only
The image channel selectivity of superheterodyne receiver depends upon$\text{IF}$ amplifiers only$\text{RF}$ and $\text{IF}$ amplifiers onlyPreselector, $\text{RF}$ and $...
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GATE ECE 1998 | Question 2.18
In a $\text{PCM}$ system with uniform quantisation, increasing the number of bits from $8$ to $9$ will reduce the quantisation noise power by a factor of $9$ $8$ $4$ $2$
In a $\text{PCM}$ system with uniform quantisation, increasing the number of bits from $8$ to $9$ will reduce the quantisation noise power by a factor of$9$$8$$4$$2$
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GATE ECE 1998 | Question 2.19
The Fourier transform of a function $x(t)$ is $\mathrm{X}(f)$. The Fourier transform of $\frac{d \mathrm{X}(f)}{d f}$ will be $\frac{dX(f)}{d f}$ $j 2 \pi f X(f)$ $jf X(f)$ $\frac{X(f)}{if}$
The Fourier transform of a function $x(t)$ is $\mathrm{X}(f)$. The Fourier transform of $\frac{d \mathrm{X}(f)}{d f}$ will be$\frac{dX(f)}{d f}$$j 2 \pi f X(f)$$jf X(f)$$...
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GATE ECE 1998 | Question 2.20
Flat top sampling of low pass signals gives rise to aperture effect implies oversampling leads to aliasing introduces delay distortion
Flat top sampling of low pass signalsgives rise to aperture effectimplies oversamplingleads to aliasingintroduces delay distortion
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GATE ECE 1998 | Question 2.21
A $\text{DSB-SC}$ signal is generated using the carrier $\cos \left(\omega_{c}, t+\theta\right)$ and modulating signal $x(t)$. The envelope of the $\text{DSB-SC}$ signal is $x(t)$ $|x(t)|$ only positive portion of $x(t)$ $x(t) \cos \theta$
A $\text{DSB-SC}$ signal is generated using the carrier $\cos \left(\omega_{c}, t+\theta\right)$ and modulating signal $x(t)$. The envelope of the $\text{DSB-SC}$ signal ...
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GATE ECE 1998 | Question 2.22
Quadrature multiplexing is the same as $\text{FDM}$ the same as $\text{TDM}$ a combination of $\text{FDM}$ and $\text{TDM}$ quite different from $\text{FDM}$ and $\text{TDM}$
Quadrature multiplexing isthe same as $\text{FDM}$the same as $\text{TDM}$a combination of $\text{FDM}$ and $\text{TDM}$quite different from $\text{FDM}$ and $\text{TDM}$...
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GATE ECE 1998 | Question 2.23
The Fourier transform of a voltage signal $x(t)$ is $X(f)$. The unit of $|X(f)|$ is volt volt-sec volt/sec volt $^{2}$
The Fourier transform of a voltage signal $x(t)$ is $X(f)$. The unit of $|X(f)|$ isvoltvolt-secvolt/secvolt $^{2}$
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GATE ECE 1998 | Question 2.24
Compression in $\text{PCM}$ refers to relative compression of higher signal amplitudes lower signal amplitudes lower signal frequencies higher signal frequencies
Compression in $\text{PCM}$ refers to relative compression ofhigher signal amplitudeslower signal amplitudeslower signal frequencieshigher signal frequencies
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GATE ECE 1998 | Question 2.25
For a given data rate, the bandwidth $\mathrm{B}_{p}$ of a $\text{BPSK}$ signal and the bandwidth $\text{B}_{0}$ of the $\mathrm{OOK}$ signal are related as $\mathrm{B}_{p}=\frac{\mathrm{B}_{0}}{4}$ $\text{B}_{p}=\frac{\text{B}_{0}}{2}$ $\mathrm{B}_{p}=\mathrm{B}_{0}$ $\text{B}_{p}=\text{2B}_{0}$
For a given data rate, the bandwidth $\mathrm{B}_{p}$ of a $\text{BPSK}$ signal and the bandwidth $\text{B}_{0}$ of the $\mathrm{OOK}$ signal are related as$\mathrm{B}_{p...
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GATE ECE 1998 | Question 2.26
The spectral density of a real valued random process has an even symmetry an odd symmetry a conjugate symmetry no symmetry
The spectral density of a real valued random process hasan even symmetryan odd symmetrya conjugate symmetryno symmetry
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GATE ECE 1998 | Question 2.27
The probability density function of the envelope of narrow band Gaussian noise is Poisson Gaussian Rayleigh Rician
The probability density function of the envelope of narrow band Gaussian noise isPoissonGaussianRayleighRician
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GATE ECE 1998 | Question 2.28
The intrinsic impedance of copper at high frequencies is purely resistive purely inductive complex with a capacitive component complex with an inductive component
The intrinsic impedance of copper at high frequencies ispurely resistivepurely inductivecomplex with a capacitive componentcomplex with an inductive component
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GATE ECE 1998 | Question 2.29
The Maxwell equation $\mathrm{V} \times \mathrm{H}=\mathrm{J}+\frac{\partial \overline{D}}{\partial t}$ is based on Ampere's law Gauss' law Faraday's law Coulomb's law
The Maxwell equation $\mathrm{V} \times \mathrm{H}=\mathrm{J}+\frac{\partial \overline{D}}{\partial t}$ is based onAmpere's lawGauss' lawFaraday's lawCoulomb's law
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GATE ECE 1998 | Question 2.30
All transmission line sections shown in the figure is have a characteristic impedance $\text{R}_{0}+\text{j}_{0}$. The input impedance $\text{Z}_{\text {in}}$ equals $\frac{2}{3} \text{R}_{0}$ $\mathrm{R}_{0}$ $\frac{3}{2} \text{R}_{0}$ $2 \mathrm{R}_{\mathrm{0}}$
All transmission line sections shown in the figure is have a characteristic impedance $\text{R}_{0}+\text{j}_{0}$. The input impedance $\text{Z}_{\text {in}}$ equals$\fra...
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GATE ECE 1998 | Question 2.31
The time averages Poynting vector, in $W / m^{2}$, for a wave with $\vec{E}=24 \; e^{} \; a_{} \mathrm{~V} / \mathrm{m}$ in free space is $ – \frac{2.4}{\pi} \vec{a}_{z}$ $\frac{2.4}{\pi} \vec{a}_{z}$ $\frac{4.8}{\pi} \vec{a}_{z}$ $-\frac{4.8}{\pi} \vec{a}_{z}$
The time averages Poynting vector, in $W / m^{2}$, for a wave with $\vec{E}=24 \; e^{} \; a_{} \mathrm{~V} / \mathrm{m}$ in free space is$ – \frac{2.4}{\pi} \vec{a}_{z}...
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GATE ECE 1998 | Question 2.32
The wavelength of a wave with propagation constant $(0.1 \pi+j 0.2 \pi) \mathrm{m}^{-1}$ is $\frac{2}{\sqrt{0.05}} \mathrm{~m}$ $10 \mathrm{~m}$ $20 \mathrm{~m}$ $30 \mathrm{~m}$
The wavelength of a wave with propagation constant $(0.1 \pi+j 0.2 \pi) \mathrm{m}^{-1}$ is$\frac{2}{\sqrt{0.05}} \mathrm{~m}$$10 \mathrm{~m}$$20 \mathrm{~m}$$30 \mathrm{...
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GATE ECE 1998 | Question 2.33
The depth of penetration of wave in a lossy dielectric increases with increasing conductivity permeability wavelength permittivity
The depth of penetration of wave in a lossy dielectric increases with increasingconductivitypermeabilitywavelengthpermittivity
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GATE ECE 1998 | Question 2.34
The polarisation of wave with electric field vector $\overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \; e^{j(\hat{\rho}(\omega t+\beta z)}\left(\vec{a}_{x}+\vec{a}_{y}\right)$ is linear elliptical left hand circular right hand circular
The polarisation of wave with electric field vector$\overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \; e^{j(\hat{\rho}(\omega t+\beta z)}\left(\vec{a}_{x}+\vec{a}_{y}\right)$ ...
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GATE ECE 1998 | Question 2.35
The vector $\mathrm{H}$ in the far field of an antenna satisfies $\nabla \cdot \overrightarrow{\mathrm{H}}=0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$ $\nabla \cdot \overrightarrow{\mathrm{H}} \neq 0$ ... $\nabla \cdot \overrightarrow{\mathrm{H}} \neq 0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$
The vector $\mathrm{H}$ in the far field of an antenna satisfies$\nabla \cdot \overrightarrow{\mathrm{H}}=0$ and $\nabla \times \overrightarrow{\mathrm{H}}=0$$\nabla \cdo...
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GATE ECE 1998 | Question 2.36
The radiation resistance of a circular loop of one turn is $0.01 \; \Omega$. The radiation resistance of five turns of such a loop will be $0.002 \; \Omega$ $0.01 \; \Omega$ $0.05 \; \Omega$ $0.25 \; \Omega$
The radiation resistance of a circular loop of one turn is $0.01 \; \Omega$. The radiation resistance of five turns of such a loop will be$0.002 \; \Omega$$0.01 \; \Omega...
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GATE ECE 1998 | Question 2.37
An antenna in free space receives $2 \; \mu \mathrm{W}$ of power when the incident electric field is $20 \mathrm{~m} \; \mathrm{V} / \mathrm{m} \; \mathrm{rms}$. The effective aperture of the antenna is $0.005 \mathrm{~m}^{2}$ $0.05 \mathrm{~m}^{2}$ $1.885 \mathrm{~m}^{2}$ $3.77 \mathrm{~m}^{2}$
An antenna in free space receives $2 \; \mu \mathrm{W}$ of power when the incident electric field is $20 \mathrm{~m} \; \mathrm{V} / \mathrm{m} \; \mathrm{rms}$. The effe...
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GATE ECE 1998 | Question 2.38
The maximum usable frequency of an ionospheric layer at $60^{\circ}$ incidence and with $8 \; \mathrm{mHz}$ critical frequency is $16 \; \mathrm{MHz}$ $\frac{16}{\sqrt{3}} \; \mathrm{MHz}$ $8 \; \mathrm{MHz}$ about $6.93 \; \mathrm{MHz}$
The maximum usable frequency of an ionospheric layer at $60^{\circ}$ incidence and with $8 \; \mathrm{mHz}$ critical frequency is$16 \; \mathrm{MHz}$$\frac{16}{\sqrt{3}} ...
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GATE ECE 1998 | Question 2.39
A loop is rotating about the $y$-axis in a magnetic field $\overrightarrow{\mathrm{E}}=\mathrm{B}_{0} \cos (\omega t+\phi) \vec{a}_{x} \mathrm{~T}$. The voltage in the loop is zero due to rotation only due to transformer action only due to both rotation and transformer action
A loop is rotating about the $y$-axis in a magnetic field $\overrightarrow{\mathrm{E}}=\mathrm{B}_{0} \cos (\omega t+\phi) \vec{a}_{x} \mathrm{~T}$. The voltage in the lo...
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GATE ECE 1998 | Question 2.40
The far field of an antenna varies with distance $\mathrm{r}$ as $\frac{1}{r}$ $\frac{1}{r^{2}}$ $\frac{1}{r^{3}}$ $\frac{1}{\sqrt{r}}$
The far field of an antenna varies with distance $\mathrm{r}$ as$\frac{1}{r}$$\frac{1}{r^{2}}$$\frac{1}{r^{3}}$$\frac{1}{\sqrt{r}}$
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