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Consider a solid sphere and a hollow sphere, both of mass $M$, radius $R$ and initially at rest, which start rolling down the same inclined plane without slipping. At the bottom of the inclined plane, the ratio of speeds $\mathrm{V}^{\text {solid }} / \mathrm{V}^{\text {hollow }}$ is

  1. $1$
  2. $\sqrt{12 / 7}$
  3. $\sqrt{10 / 7}$
  4. $\sqrt{25 / 21}$

[Note : The moment of inertia about any diameter for a solid sphere is $(2 / 5) \mathrm{MR}^{2}$, and for a hollow sphere $(2 / 3) \mathrm{MR}^{2}$ ]

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Ans: D

Hint : Energy conservation (mechanical): initial gravitational potential Mgh converts into translational kinetic energy  and rotational kinetic energy .

Mgh  =  1/2Mv^2  +  1/2Iω^2. , where w= V/R 

 

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