0 0 votes The current, $\text{i(t)}$, through a $10 \; \Omega$ resistor in series with an inductance, is given by $i(t)=3+4 \sin \left(100 t+45^{\circ}\right)+4 \sin \left(300 t+60^{\circ}\right)$ Amperes The $\text{RMS}$ value of the current and the power dissipated in the circuit are : $\sqrt{41} \mathrm{~A}, 410 \mathrm{~W}$, respectively $\sqrt{35} \mathrm{~A}, 350 \mathrm{~W}$, respectively $5 \mathrm{~A}, 250 \mathrm{~W}$, respectively $11 \mathrm{~A}, 1210 \mathrm{~W}$, respectively Circuit Analysis gate1995-ec circuit-analysis numerical-answers + – admin 355 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
