If $A=\left[\begin{array}{cc}-2 & 2 \\ 1 & -3\end{array}\right]$, then $\sin A t$ is
- $\frac{1}{3}\left[\begin{array}{cc}\sin (-4 t)+2 \sin (-t) & -2 \sin (-4 t)+2 \sin (-t) \\ -\sin (-4 t)+\sin (-t) & 2 \sin (-4 t)+\sin (-t)\end{array}\right]$
- $\left[\begin{array}{rr}\sin (-2 t) & \sin (2 t) \\ \sin (t) & \sin (-3 t)\end{array}\right]$
- $\frac{1}{3}\left[\begin{array}{lc}\sin (4 t)+2 \sin (t) & 2 \sin (-4 t)-2 \sin (-t) \\ -\sin (-4 t)+\sin (t) & 2 \sin (4 t)+\sin (t)\end{array}\right]$
- $\frac{1}{3}\left[\begin{array}{ll}\cos (-t)+2 \cos (t) & -2 \cos (-4 t)+2 \sin (-t) \\ -\cos (-4 t)+\sin (-t) & -2 \cos (-4 t)+\cos (-t)\end{array}\right]$