0 0 votes Consider the signal flow graph shown in the figure below. The gain $\frac{x_{5}}{x_{1}}$ is $\frac{1-\left(b e+c f+d g\right)}{a b c}$ $\frac{b e d g}{1-(b e+c f+d g)}$ $\frac{a b c d}{1-\left(b e+c f+d g\right)+bedg}$ $\frac{1-\left(b e+cf+d g\right)+b ed g}{a b c d}$ Control Systems gate2004-ec control-systems signal-flow-graph transfer-function + – admin 247 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.