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Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(\frac{1}{2})^nu[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y[1]=\frac{1}{2}$, then $g[1]$ equals

  1. $0$
  2. $\frac{1}{2}$
  3. $1$
  4. $\frac{3}{2}$
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