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Recent questions tagged convolution
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GATE ECE 2015 Set 3 | Question: 45
Consider a continuous-time signal defined as $x(t)=\left(\dfrac{\sin(\pi t/2)}{(\pi t /2)}\right)\ast \sum _{n=-\infty}^{\infty}\delta(t-10n)$ where $’\ast’$ denotes the convolution operation and $t$ is in seconds. The Nyquist sampling rate $\text{(in samples/sec)}$ for $x(t)$ is _______.
Consider a continuous-time signal defined as$$x(t)=\left(\dfrac{\sin(\pi t/2)}{(\pi t /2)}\right)\ast \sum _{n=-\infty}^{\infty}\delta(t-10n)$$where $’\ast’$ denotes ...
Milicevic3306
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Milicevic3306
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Mar 27, 2018
Continuous-time Signals
gate2015-ec-3
numerical-answers
continuous-time-signals
convolution
nyquist
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GATE ECE 2015 Set 1 | Question: 17
The result of the convolution $x(-t) * \delta (-t-t_0)$ is $x(t+t_0)$ $x(t-t_0)$ $x(-t+t_0)$ $x(-t – t_0)$
The result of the convolution $x(-t) * \delta (-t-t_0)$ is$x(t+t_0)$$x(t-t_0)$$x(-t+t_0)$$x(-t – t_0)$
Milicevic3306
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Milicevic3306
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Mar 27, 2018
Continuous-time Signals
gate2015-ec-1
continuous-time-signals
signals-and-system
convolution
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3
GATE ECE 2012 | Question: 42
Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(\frac{1}{2})^nu[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y[1]=\frac{1}{2}$, then $g[1]$ equals $0$ $\frac{1}{2}$ $1$ $\frac{3}{2}$
Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(\frac{1}{2})^nu[n]$ and $g[n]$ is a casual sequence. If $y[0]=1$ and $y =\frac{1}{2}$, then $g $ equa...
Milicevic3306
16.0k
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95
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Milicevic3306
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Mar 25, 2018
Continuous-time Signals
gate2012-ec
continuous-time-signals
signals-and-systems
convolution
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