recategorized by
401 views
0 0 votes

A system described by the following differential equation $\frac{d^{2} y}{d t^{2}}+3 \frac{d y}{d t}+2 y=x(t)$ is initially at rest. For input $x(t)=2 u(t)$, the output $y(t)$ is

  1. $\left(1-2 e^{-t}+e^{-2 t}\right) u(t)$
  2. $\left(1+2 e^{-t}-2 e^{-2 t}\right) u(t)$
  3. $\left(0.5+e^{-t}+1.5 e^{-2 t}\right) u(t)$
  4. $\left(0.5+2 e^{-1}+2 e^{-2 t}\right) u(t)$

Please log in or register to answer this question.

Answer:
Position:
Show:

Related questions

0 0 votes
0 0 answers
312
312 views
admin asked Sep 25, 2022
312 views
For the $\text{R-L}$ circuit shown in the figure, the input voltage $v_{i}(t)=u(t)$. The current $i(t)$ is
1 1 vote
0 0 answers
354
354 views
admin asked Sep 15, 2022
354 views
A continuous time $\text{LTI}$ system is described by\[ \frac{d^{2} y(t)}{d t^{2}}+4 \frac{d y(t)}{d t}+3 y(t)=2 \frac{d x(t)}{d t}+4 x(t) \]Assuming zero initial conditi...
0 0 votes
0 0 answers
344
344 views
admin asked Sep 25, 2022
344 views
A causal system having the transfer function $\mathrm{H}(s)=\frac{1}{s+2}$ is excited with $10 u(t)$. The time at which the output reaches $99 \%$ of its steady state val...
0 0 votes
0 0 answers
362
362 views
admin asked Sep 25, 2022
362 views
For the circuit shown in the figure, the initial conditions are zero. Its transfer function$$ H(s) = \frac{V_{c}(s)}{V_{i}(s)}$$$\frac{1}{s^{2}+10^{6} s+10^{6}}$$\frac{10...

Add Synced Question

×