0 0 votes Two identical antennas are placed in the $\theta=\pi / 2$ plane as shown in the figure. The elements have equal amplitude excitation with $180^{\circ}$ polarity difference, operating at wavelength $\lambda$. The correct value of the magnitude of the far-zone resultant electric field strength normalized with that of a single element, both computed for $\phi=0$, is $2 \cos \left(\frac{2 \pi s}{\lambda}\right)$ $2 \sin \left(\frac{2 \pi s}{\lambda}\right)$ $2 \cos \left(\frac{\pi s}{\lambda}\right)$ $2 \sin \left(\frac{\pi \mathrm{s}}{\lambda}\right)$ Antennas gate2003-ec antennas electromagnetics plane-waves-and-properties + – admin 329 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
