0 0 votes A superheterodyne receiver is to operate in the frequency range $550 \; \mathrm{kHz}-1650 \; \mathrm{kHz}$, with the intermediate frequency of $450 \; \mathrm{kHz}$. Let $\mathrm{R}=\frac{\mathrm{C}_{\operatorname{max}}}{\mathrm{C}_{\text {min}}}$ denote the required capacitance ratio of the local oscillator and $\text{I}$ denote the image frequency (in $\mathrm{kHz}$ ) of the incoming signal. If the receiver is tuned to $700 \; \mathrm{kHz}$, then $\mathrm{R}=4.41, \mathrm{I}=1600$ $\mathrm{R}=2.10, \text{I}=1150$ $\mathrm{R}=3.0, \mathrm{I}=1600 \quad$ $\mathrm{R}=9.0, \mathrm{I}=1150$ Analog Communications gate2003-ec analog-communications + – admin 417 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
