In the amplifier circuit shown in the figure is the values of $R_{1}$ and $R_{2}$ are such that the transistor is operating at $\mathrm{V}_{\mathrm{CE}}=3 \mathrm{~V}$ and $\mathrm{I}_{\mathrm{C}}=1.5 \mathrm{~mA}$ when its $\beta$ is $150.$ For a transistor with $\beta$ of $200,$ the operating point $\left(\mathrm{V}_{\mathrm{CE},} \mathrm{I}_{\mathrm{C}}\right)$ is
- $(2 \mathrm{~V}, 2 \mathrm{~mA})$
- $(3 \mathrm{~V}, 2 \mathrm{~mA})$
- $(4 \mathrm{~V}, 2 \mathrm{~mA})$
- $(4 \mathrm{~V}, 1 \mathrm{~mA})$