0 votes 0 votes The transfer function of a zero-order-hold system is $(1 / s)\left(1+e^{-sT}\right)$ $(1 / s)\left(1-e^{-sT}\right)$ $1-(1 / s) e^{-sT}$ $1+(1 / s) e^{-s T}$ Others gate1998-ec + – admin asked Sep 26, 2022 • edited Dec 1, 2023 by makhdoom ghaya admin 46.4k points 102 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.