0 0 votes The Bode plot of a transfer function $G(s)$ is shown in the figure below. The gain $(20\log \mid G(s)\mid)$ is $32\:dB$ and $-8\:dB$ at $1\:rad/s$ and $10\:rad/s$ respectively. The phase is negative for all $\omega.$ Then $G(s)$ is $\frac{39.8}{s} \\$ $\frac{39.8}{s^{2}} \\$ $\frac{32}{s} \\$ $\frac{32}{s^{2}} \\$ Control Systems gate2013-ec control-systems bode-and-root-locus-plots + – Milicevic3306 481 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.