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The Bode plot of a transfer function $G(s)$ is shown in the figure below.

The gain $(20\log \mid G(s)\mid)$ is $32\:dB$ and $-8\:dB$ at $1\:rad/s$ and $10\:rad/s$ respectively. The phase is negative for all $\omega.$ Then $G(s)$ is

- $\frac{39.8}{s} \\$
- $\frac{39.8}{s^{2}} \\$
- $\frac{32}{s} \\$
- $\frac{32}{s^{2}} \\$