Electronis Discussion

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A region shown below contains a perfect conducting half-space and air. The surface current $\overrightarrow{K_{s}}$ on the surface of the perfect conductor is $\overrightarrow{K_{s}}= \hat{x}2$ amperes per meter. The tangential $\overrightarrow{H}$ field in the air just above the perfect conductor is

- $( \hat{x} +\hat{z})2$ amperes per meter
- $\hat{x}2$ amperes per meter
- $-\hat{z}2$ amperes per meter
- $\hat{z}2$ amperes per meter

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