0 0 votes A region shown below contains a perfect conducting half-space and air. The surface current $\overrightarrow{K_{s}}$ on the surface of the perfect conductor is $\overrightarrow{K_{s}}= \hat{x}2$ amperes per meter. The tangential $\overrightarrow{H}$ field in the air just above the perfect conductor is $( \hat{x} +\hat{z})2$ amperes per meter $\hat{x}2$ amperes per meter $-\hat{z}2$ amperes per meter $\hat{z}2$ amperes per meter Number Representations gate2014-ec-3 digital-circuits + – Milicevic3306 534 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.