in Electronic Devices recategorized by
63 views
0 votes
0 votes

The parallel-plate capacitor shown in the figure has movable plates. The capacitor is charged so that the energy stored in it is $E$ when the plate separation is $d$. The capacitor is then isolated electrically and the plate are moved such that the plate separation becomes $2d$.

                                                          

At this new plate separation, what is the energy stored in the capacitor, neglecting fringing effects?

  1. $2E$
  2. $\sqrt{2}E$
  3. $E$
  4. $E/2$
in Electronic Devices recategorized by
15.8k points
63 views

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.