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Following is the K-map of a Boolean function of five variables $P,Q,R,S$ and $X$. The minimum sum-of-product (SOP) expression for the function is

  1. $\overline{P}\:\overline{Q}\:S\:\overline{X}+\;P\:\overline{Q}\:S\:\overline{X}+\;Q\:\overline{R}\:\overline{S}\:X+\;Q\:R\:\overline{S}\:X$
  2. $\overline{Q}\:S\:\overline{X}+\;Q\:\overline{S}\:X$
  3. $\overline{Q}\:S\:X+\;Q\:\overline{S}\:\overline{X}$
  4. $\overline{Q}\:S+\;Q\overline{S}$

1 Answer

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The given boolean function $f(P,Q,R,S,X)$ has the following behavior:

When $X = 0,$ $f = Q’S$

When $X = 1, f = QS’$

So, we can write expression for $f$ as following: $f = X’ Q’S + X Q S’$

We can’t simplify it further. So, answer is Option B.
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