GO Electronics
Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
Recent
Hot!
Most votes
Most answers
Most views
Previous GATE
Featured
Hot questions
0
votes
0
answers
401
GATE ECE 1997 | Question 3.6
A communication channel has first-order low pass transfer function. The channel is used to transmit pulses at a symbol rate greater than the half-power frequency of the low pass function. Which of the network shown in the figure is can be used to equalise the received pulses?
A communication channel has first-order low pass transfer function. The channel is used to transmit pulses at a symbol rate greater than the half-power frequency of the l...
admin
46.4k
points
211
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
402
GATE ECE 1997 | Question 2.4
In a common emitter $\text{BJT}$ amplifier, the maximum usable supply voltage is limited by Avalanche breakdown of Base-Emitter junction Collector-Base breakdown voltage with emitter open $\left(\mathrm{BV}_{\mathrm{CBO}}\right)$ Collector-Emitter breakdown ... with base open $\left(\mathrm{BV}_{\mathrm{CBO}}\right)$ Zener breakdown voltage of the Emitter-Base junction
In a common emitter $\text{BJT}$ amplifier, the maximum usable supply voltage is limited byAvalanche breakdown of Base-Emitter junctionCollector-Base breakdown voltage wi...
admin
46.4k
points
209
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
403
GATE ECE 1997 | Question 1.11
The voltage $V$ in the figure is $10 \mathrm{~V}$ $15 \mathrm{~V}$ $5 \mathrm{~V}$ None of the above
The voltage $V$ in the figure is$10 \mathrm{~V}$$15 \mathrm{~V}$$5 \mathrm{~V}$None of the above
admin
46.4k
points
204
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
404
GATE ECE 2000 | Question 2.14
In given figure, the steady state output voltage corresponding to the input voltage $3+4 \sin 100 t \mathrm{~V}$ is $3+\frac{4}{\sqrt{2}} \sin \left(100 t-\frac{\pi}{4}\right) \mathrm{V}$ $3+4 \sqrt{2} \sin \left(100 t-\frac{\pi}{4}\right) \mathrm{V}$ ... $3+4 \sin \left(100 t \div \frac{\pi}{4}\right) \mathrm{V}$
In given figure, the steady state output voltage corresponding to the input voltage $3+4 \sin 100 t \mathrm{~V}$ is$3+\frac{4}{\sqrt{2}} \sin \left(100 t-\frac{\pi}{4}\ri...
admin
46.4k
points
319
views
admin
asked
Sep 29, 2022
Others
gate2000-ec
+
–
0
votes
0
answers
405
GATE ECE 1997 | Question 4.4
A signed integer has been stored in a byte using the $2$'s complement format. We wish to store the same integer in a $16$ bit word. We should copy the original byte to the less significant byte of the word and fill the more ... significant bit of the original byte copy the original byte to the less significant byte as well as the more significant byte of the word
A signed integer has been stored in a byte using the $2$'s complement format. We wish to store the same integer in a $16$ bit word. We shouldcopy the original byte to the...
admin
46.4k
points
173
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
406
GATE ECE 1997 | Question 2.1
In the $\text{BJT}$ amplifier shown in the figure is the transistor is based in the forward active region. Putting a capacitor across $R_E$ will decrease the voltage gain and decrease the input impedance increase the voltage gain ... the input impedance decrease the voltage gain and increase the input impedance increase the voltage gain and increase the input impedance
In the $\text{BJT}$ amplifier shown in the figure is the transistor is based in the forward active region. Putting a capacitor across $R_E$ will decrease the voltage gain...
admin
46.4k
points
167
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
407
GATE ECE 1997 | Question 3.7
The power spectral density of a deterministic signal is given by $\left[\sin (f) / f^{2}\right]$ where $f$ is frequency. The autocorrelation function of this signal in the time domain is a rectangular pulse a delta function a sine pulse a triangular pulse
The power spectral density of a deterministic signal is given by $\left[\sin (f) / f^{2}\right]$ where $f$ is frequency. The autocorrelation function of this signal in th...
admin
46.4k
points
159
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
408
GATE ECE 1997 | Question 1.3
The voltage $\mathrm{V}$ in the figure is always equal to $9 \mathrm{~V}$ $5 \mathrm{~V}$ $1 \mathrm{~V}$ None of the above
The voltage $\mathrm{V}$ in the figure is always equal to$9 \mathrm{~V}$$5 \mathrm{~V}$$1 \mathrm{~V}$None of the above
admin
46.4k
points
156
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
409
GATE ECE 1997 | Question 2.9
The output of the logic gate in the figure is $0$ $1$ $\text{A}$ $\mathrm{F}$
The output of the logic gate in the figure is$0$$1$$\text{A}$$\mathrm{F}$
admin
46.4k
points
155
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
410
GATE ECE 1997 | Question 2.2
A cascade amplifier stage is equivalent to a common emitter stage followed by a common base stage a common base stage followed by an emitter follower an emitter follower stage followed by a common base stage a common base stage followed by a common emitter stage
A cascade amplifier stage is equivalent toa common emitter stage followed by a common base stagea common base stage followed by an emitter followeran emitter follower sta...
admin
46.4k
points
153
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
411
GATE ECE 1997 | Question 4.8
In a $\text{J-K}$ flip-flip we have $\text{J=Q}$ and $\text{K}=1$. Assuming the flip flop was initially cleared and then clocked for $6$ puleses, the sequence at the $\text{Q}$ output will be $010000$ $011001$ $010010$ $010101$
In a $\text{J-K}$ flip-flip we have $\text{J=Q}$ and $\text{K}=1$. Assuming the flip flop was initially cleared and then clocked for $6$ puleses, the sequence at the $\te...
admin
46.4k
points
153
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
412
GATE ECE 1997 | Question 3.5
A certain linear time invariant system has the state and the output equations given below \[ \begin{array}{c} {\left[\begin{array}{l} \dot{\mathrm{X}}_{1} \\ \dot{\mathrm{X}}_{2} \end{array}\right]=\left[\begin{array}{rr} 1 & -1 \\ 0 & 1 \end{array}\right]\left[\ ... $\left.\frac{d y}{d t}\right|_{t=0}$ is $1$ $-1$ $0$ None of the above
A certain linear time invariant system has the state and the output equations given below\[\begin{array}{c}{\left[\begin{array}{l}\dot{\mathrm{X}}_{1} \\\dot{\mathrm{X}}_...
admin
46.4k
points
152
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
413
GATE ECE 1997 | Question 3.2
In the circuit of the figure is the equivalent impedance seen across terminals $\text{a, b}$ is $\left(\frac{16}{3}\right) \Omega$ $\left(\frac{8}{3}\right) \Omega$ $\left(\frac{8}{3}+12 j\right) \Omega$ None of the above
In the circuit of the figure is the equivalent impedance seen across terminals $\text{a, b}$ is$\left(\frac{16}{3}\right) \Omega$$\left(\frac{8}{3}\right) \Omega$$\left(\...
admin
46.4k
points
144
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
414
GATE ECE 1997 | Question 3.9
A parabolic dish antenna has a conical beam $2^{\circ}$ wide, the directivity of the antenna is approximately $20 \; d \mathrm{B}$ $30 \; d \mathrm{B}$ $40 \; d \mathrm{B}$ $50 \; d \mathrm{B}$
A parabolic dish antenna has a conical beam $2^{\circ}$ wide, the directivity of the antenna is approximately$20 \; d \mathrm{B}$$30 \; d \mathrm{B}$$40 \; d \mathrm{B}$$...
admin
46.4k
points
143
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
415
GATE ECE 1997 | Question 2.3
For a $\text{MOS}$ capacitor fabricated on a $p$-type semiconductor, strong inversion occurs when surface potential is equal to Fermi potential surface potential is zero surface potential is negative and equal to Fermi potential in magnitude surface potential is positive and equal to twice the Fermi potential
For a $\text{MOS}$ capacitor fabricated on a $p$-type semiconductor, strong inversion occurs whensurface potential is equal to Fermi potentialsurface potential is zerosur...
admin
46.4k
points
134
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
416
GATE ECE 1997 | Question 1.9
A probability density fucntion is given by $p(x)=\mathrm{K} e^{-x^2 / 2}-\infty<x<\infty$. The value of $K$ should be $\frac{1}{\sqrt{2 \pi}}$ $\sqrt{\frac{2}{\pi}}$ $\frac{1}{2 \sqrt{\pi}}$ $\frac{1}{\pi \sqrt{2}}$
A probability density fucntion is given by $p(x)=\mathrm{K} e^{-x^2 / 2}-\infty<x<\infty$. The value of $K$ should be$\frac{1}{\sqrt{2 \pi}}$$\sqrt{\frac{2}{\pi}}$$\frac{...
admin
46.4k
points
133
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
417
GATE ECE 1997 | Question 2.7
In standard $\text{TTL}$, the 'totem pole' stage refers to the multi-emitter input stage the phase splitter the output buffer open collector output stage
In standard $\text{TTL}$, the 'totem pole' stage refers tothe multi-emitter input stagethe phase splitterthe output bufferopen collector output stage
admin
46.4k
points
132
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
418
GATE ECE 2000 | Question 1.14
The amplitude modulated wave form $s(t)=A_{c}\left[1+K_{a} m(t)\right] \cos \omega_{c} t$ is fed to an ideal envelope detector. The maximum magnitude of $\mathrm{K}_{0} m(t)$ is greater than $1$ ... $\mathrm{A}_{c}\left[1+\mathrm{K}_{a} m(t)\right]^{2}$
The amplitude modulated wave form $s(t)=A_{c}\left[1+K_{a} m(t)\right] \cos \omega_{c} t$ is fed to an ideal envelope detector. The maximum magnitude of $\mathrm{K}_{0} m...
admin
46.4k
points
256
views
admin
asked
Sep 29, 2022
Others
gate2000-ec
+
–
0
votes
0
answers
419
GATE ECE 1997 | Question 4.3
The following insturctions have been executed by an $8085 \; \mu \mathrm{P}$ ... $6019$ $6379$ $6979$ None of the above
The following insturctions have been executed by an $8085 \; \mu \mathrm{P}$$\begin{array}{cl}\text { ADDRESS (HEX) } & \text { INSTRUCTION } \\ 6010 & \text { LXI H, 8A ...
admin
46.4k
points
130
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
420
GATE ECE 1997 | Question 1.6
A transmission line of $50 \; \Omega$ characteristic impedance is terminated with a $100 \; \Omega$ resistance. The minimum impedance measured on the line is equal to $0 \; \Omega$ $25 \; \Omega$ $50 \; \Omega$ $100 \; \Omega$
A transmission line of $50 \; \Omega$ characteristic impedance is terminated with a $100 \; \Omega$ resistance. The minimum impedance measured on the line is equal to$0 ...
admin
46.4k
points
130
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
421
GATE ECE 1997 | Question: 1.2
The voltage $\mathrm{V}$ in the figure is equal to $3 \mathrm{~V}$ $-3 \mathrm{~V}$ $5 \mathrm{~V}$ None of these
The voltage $\mathrm{V}$ in the figure is equal to$3 \mathrm{~V}$$-3 \mathrm{~V}$$5 \mathrm{~V}$None of these
admin
46.4k
points
130
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
422
GATE ECE 1997 | Question 1.7
A rectangular air-filled waveguide has cross section of $4 \mathrm{~cm} \times 10 \mathrm{~cm}$. The minimum frequency which can propagate in the waveguide is $1.5\; \mathrm{GHz}$ $2.0\; \mathrm{GHz}$ $2.5\; \mathrm{GHz}$ $3.0\; \mathrm{GHz}$
A rectangular air-filled waveguide has cross section of $4 \mathrm{~cm} \times 10 \mathrm{~cm}$. The minimum frequency which can propagate in the waveguide is$1.5\; \math...
admin
46.4k
points
126
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
423
GATE ECE 1997 | Question 4.1
The output voltage $V_{0}$ of the circuit shown in the figure is $-4 \mathrm{~V}$ $6 \mathrm{~V}$ $5 \mathrm{~V}$ $-5.5 \mathrm{~V}$
The output voltage $V_{0}$ of the circuit shown in the figure is$-4 \mathrm{~V}$$6 \mathrm{~V}$$5 \mathrm{~V}$$-5.5 \mathrm{~V}$
admin
46.4k
points
125
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
424
GATE ECE 2000 | Question 2.11
In given figure, the $J$ and $K$ inputs of all the four Flip-Flips are made high. The frequency of the signal at output $Y$ is $0.833 \; \mathrm{kHz}$ $1.0 \; \mathrm{kHz}$ $0.91 \; \mathrm{kHz}$ $0.77 \; \mathrm{kHz}$
In given figure, the $J$ and $K$ inputs of all the four Flip-Flips are made high. The frequency of the signal at output $Y$ is$0.833 \; \mathrm{kHz}$$1.0 \; \mathrm{kHz}$...
admin
46.4k
points
249
views
admin
asked
Sep 29, 2022
Others
gate2000-ec
+
–
0
votes
0
answers
425
GATE ECE 1997 | Question 2.6
A $2$ bit binary multiplier can be implemented using $2$ inputs $\text{ANDs}$ only $2$ input $\text{XOR s}$ and $4$ input $\text{AND}$ gates only Two $2$ inputs $\text{NORs}$ and one $\text{XNOR}$ gate $\text{XOR}$ gates and shift registers
A $2$ bit binary multiplier can be implemented using$2$ inputs $\text{ANDs}$ only$2$ input $\text{XOR s}$ and $4$ input $\text{AND}$ gates onlyTwo $2$ inputs $\text{NORs}...
admin
46.4k
points
121
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
426
GATE ECE 1997 | Question 4.6
The intrinsic carrier density at $300 \mathrm{~K}$ is $1.5 \times 10^{10}$ / $\mathrm{cm}^{3}$, in silicon. For $n$-type silicon doped to $2.25 \times$ $10^{15}$ atoms $/ \mathrm{cm}^{3}$ ... $n=1.5 \times 10^{10} / \mathrm{cm}^{3}, p=1.5 \times 10^{10} / \mathrm{cm}^{3}$
The intrinsic carrier density at $300 \mathrm{~K}$ is $1.5 \times 10^{10}$ / $\mathrm{cm}^{3}$, in silicon. For $n$-type silicon doped to $2.25 \times$ $10^{15}$ atoms $/...
admin
46.4k
points
121
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
427
GATE ECE 1997 | Question 2.8
The inverter $74 \; \mathrm{ALSO} 4$ has the following specifications \[ \begin{array}{l} \mathrm{I}_{\text {OH } \max }=-0.4 \mathrm{~mA}, \mathrm{l}_{\text {OLmax }}=8 \mathrm{~mA}, \mathrm{l}_{i H_{\max }}=20 \mathrm{~mA} \text {, } \\ \mathrm{l}_{\text {iLmax }}=-0.1 \mathrm{~mA} \text {, } \end{array} \] The fan-out based on the above will be $10$ $20$ $60$ $100$
The inverter $74 \; \mathrm{ALSO} 4$ has the following specifications\[ \begin{array}{l}\mathrm{I}_{\text {OH } \max }=-0.4 \mathrm{~mA}, \mathrm{l}_{\text {OLmax }}=8 \m...
admin
46.4k
points
119
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
428
GATE ECE 1997 | Question 3.10
A very lossy, $\lambda / 4$ long, $50 \; \Omega$ transmission line is open circuited at the load end. The input impedance measured at the other end of the line is approximately $0$ $50 \; \Omega$ $\infty$ None of the above
A very lossy, $\lambda / 4$ long, $50 \; \Omega$ transmission line is open circuited at the load end. The input impedance measured at the other end of the line is approxi...
admin
46.4k
points
118
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
429
GATE ECE 1997 | Question 4.7
For the $\text{NMOS}$ logic gate shown in the figure is the logic function implemented is $\overline{\mathrm{ABCDE}}$ $(\mathrm{AB}+\overline{\mathrm{C}}) \cdot(\overline{\mathrm{D}+\mathrm{E}})$ ... $(\overline{\mathrm{A}+\mathrm{B}}) \cdot \mathrm{C}+\overline{\mathrm{D}} \cdot \overline{\mathrm{E}}$
For the $\text{NMOS}$ logic gate shown in the figure is the logic function implemented is$\overline{\mathrm{ABCDE}}$$(\mathrm{AB}+\overline{\mathrm{C}}) \cdot(\overline{\...
admin
46.4k
points
117
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
430
GATE ECE 1997 | Question 4.5
A half wave rectifier uses a diode with a forward resistance $\text{Rf}$. The voltage is $\text{V}_\text{m} \sin \omega t$ and the load resistance is $\text{R}_\text{L}$. The $\text{DC}$ ... $\frac{2 \mathrm{Vm}}{\sqrt{\pi}}$ $\frac{\mathrm{V}_{m}}{\mathrm{R}_{\mathrm{L}}}$
A half wave rectifier uses a diode with a forward resistance $\text{Rf}$. The voltage is $\text{V}_\text{m} \sin \omega t$ and the load resistance is $\text{R}_\text{L}$....
admin
46.4k
points
116
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
431
GATE ECE 1997 | Question 3.4
In the signal flow graph of the figure is $\text{y/ x}$ equals $3$ $\frac{5}{2}$ $2$ None of the above
In the signal flow graph of the figure is $\text{y/ x}$ equals$3$$\frac{5}{2}$$2$None of the above
admin
46.4k
points
114
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
432
GATE ECE 1997 | Question 3.3
In the circuit of in the figure is the current $i_{D}$ through the ideal diode (zero cut in voltage and forward resistance) equals $0 \mathrm{~A}$ $4 \mathrm{~A}$ $1 \mathrm{~A}$ None of the above
In the circuit of in the figure is the current $i_{D}$ through the ideal diode (zero cut in voltage and forward resistance) equals$0 \mathrm{~A}$$4 \mathrm{~A}$$1 \mathrm...
admin
46.4k
points
112
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
433
GATE ECE 1997 | Question 1.8
The line code that has zero $\text{dc}$ component for pulse transmission of random binary data is Non-return to zero $\text{(NRZ)}$ Retrun to zero $\text{(RZ)}$ Alternate Mark Inversion $\text{(AM)}$ None of the above
The line code that has zero $\text{dc}$ component for pulse transmission of random binary data isNon-return to zero $\text{(NRZ)}$Retrun to zero $\text{(RZ)}$Alternate Ma...
admin
46.4k
points
111
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
434
GATE ECE 1997 | Question 2.10
In an $8085 \; \mu \; \mathrm{P}$ system, the $\text{RST}$ instruction will cause an interrupt only if an interrupt service routine is not being executed only if a bit in the interrupt mask is made $0$ only if interrupts have been enabled by an $\text{El}$ instruction None of the above
In an $8085 \; \mu \; \mathrm{P}$ system, the $\text{RST}$ instruction will cause an interruptonly if an interrupt service routine is not being executedonly if a bit in t...
admin
46.4k
points
109
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
435
GATE ECE 1997 | Question 3.8
An amplifier A has $6 \; d \mathrm{B}$ gain and $50 \; \Omega$ input and output impedances. The noise figure of this amplifier as shown in the figure is $(a)$ is $3 \; d \mathrm{B}$. A cascade of two such amplifiers as in the figure is will have a noise figure of $6 \; d \mathrm{B}$ $8 \; d \mathrm{B}$ $12 \;d \mathrm{B}$ None of the above
An amplifier A has $6 \; d \mathrm{B}$ gain and $50 \; \Omega$ input and output impedances. The noise figure of this amplifier as shown in the figure is $(a)$ is $3 \; d ...
admin
46.4k
points
108
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
436
GATE ECE 1997 | Question 1.4
The function $f(t)$ has the Fourier Transform $g(\omega)$. The Fourier Transform $f f(t) g(t)\left(=\int_{-\infty}^{\infty} g(t) e^{-j \omega t} d t\right)$ is $\frac{1}{2 \pi} f(\omega)$ $\frac{1}{2 \pi} f(-\omega)$ $2 \pi f(-\omega)$ None of the above
The function $f(t)$ has the Fourier Transform $g(\omega)$. The Fourier Transform$f f(t) g(t)\left(=\int_{-\infty}^{\infty} g(t) e^{-j \omega t} d t\right)$ is$\frac{1}{2 ...
admin
46.4k
points
107
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
437
GATE ECE 1997 | Question 2.5
Each cell of a Static Random Access Memory contains $6 \; \text{MOS}$ transistors $4 \; \mathrm{MOS}$ transistors and $2$ capacitors $2 \; \text{MOS}$ transistors and $4$ capacitors $1 \; \text{MOS}$ transistor and $1$ capacitor
Each cell of a Static Random Access Memory contains$6 \; \text{MOS}$ transistors$4 \; \mathrm{MOS}$ transistors and $2$ capacitors$2 \; \text{MOS}$ transistors and $4$ ca...
admin
46.4k
points
97
views
admin
asked
Oct 2, 2022
Others
gate1997-ec
+
–
0
votes
0
answers
438
GATE ECE 2002 | Question: 2.10
The circuit in the figure is has two $\text{CMOS NOR}$-gates. This circuit functions as a flip-flop schmitt trigger nonostable multivibrator astable multivibrator
The circuit in the figure is has two $\text{CMOS NOR}$-gates. This circuit functions as aflip-flopschmitt triggernonostable multivibratorastable multivibrator
admin
46.4k
points
314
views
admin
asked
Sep 27, 2022
Others
gate2002-ec
+
–
0
votes
0
answers
439
GATE ECE 2000 | Question 1.8
An amplifier with resistive negative feedback has two left half plane poles in its open-loop transfer function. The amplifier will always be unstable at high frequencies will be stable for all frequencies may be unstable, depending on the feedback factor will oscillate at low frequencies
An amplifier with resistive negative feedback has two left half plane poles in its open-loop transfer function. The amplifierwill always be unstable at high frequencieswi...
admin
46.4k
points
214
views
admin
asked
Sep 29, 2022
Others
gate2000-ec
+
–
1
votes
0
answers
440
GATE ECE 1999 | Question 2.12
The ripple counter shown in the given figure is works as a $\bmod -3$ up counter $\bmod -5$ up counter $\bmod - 3$ down counter $\bmod - 5$ down counter
The ripple counter shown in the given figure is works as a$\bmod -3$ up counter$\bmod -5$ up counter$\bmod - 3$ down counter$\bmod - 5$ down counter
admin
46.4k
points
181
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
Page:
« prev
1
...
8
9
10
11
12
13
14
...
79
next »
GO Electronics
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register