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8 Answers

Best answer
12 12 votes

Let’s analyse each of the given options

  1. $324$

Sum of every digit $=3+2+4 = 9 =3^2$

  1. $441$

Sum of every digit $=4+4+1 = 9 =3^2$

  1. $97$

Sum of every digit $=9+7 = 16 =4^2$

  1. $64$

Sum of every digit $=6+4 = 10$

The sum of every digit in each these numbers $324,441,97$ is a perfect square whereas $64$ doesn’t produce sum as a perfect square.

By this logic, option D is the correct answer.


  1. $324=(18)^2 $
  1. $441=(21)^2$
  1. $97$ is not a perfect square of any number.
  1. $64=(8)^2$

By this logic, option C is the correct answer.


Hence both options C and D are correct.

As per Official answer key, both options C and D are correct.

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13 13 votes

Ans. (C)

$324 = (18)^2$ 

$441 = (21)^2$

$64 = (8)^2$

Where as $97$ is not perfect square of any number.

Therefore, ans is (c)

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97 is the only prime no among all of them.

so option C is correct.

but when we give a little more effort then we get that the D option is also correct as the sum of the digit of every number is a perfect square except 64. so C, and D is the correct option but if in an exam this type of question comes in MCQ  then they give marks to all.
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