0 0 votes The dispersion equation of a waveguide, which relates the wavenumber $k$ to the frequency $\omega$ is $$k(\omega)= (1/c) \sqrt{\omega^{2}-\omega_{\circ}^{2}}$$ where the speed of light $c= 2 \times 10^{8}\: m/s$ and $\omega_{\circ}$ is a constant . If the group velocity is $2 \times 10^{8}\: m/s$, then the phase velocity is $1.5 \times 10^{8} \:m/s$ $2 \times 10^{8}\: m/s$ $3 \times 10^{8}\: m/s$ $4.5 \times 10^{8}\: m/s$ Electromagnetics gate2019-ec electromagnetics waveguides + – Arjun 516 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
