recategorized by
515 views
3 votes
3 votes

The output $\mathrm{Y}$ in the circuit below is always $\text{“1"}$ when

  1. two or more of the inputs $\mathrm{P, Q, R}$ are $\text{“0"}$
  2. two or more of the inputs $\mathrm{P, Q, R}$ are $\text{“1"}$
  3. any odd number of the inputs $\mathrm{P, Q, R}$ is $\text{“0"}$
  4. any odd number of the inputs $\mathrm{P, Q, R}$ is $\text{“1"}$
recategorized by

2 Answers

1 votes
1 votes
$Y = PQ + PR + QR$

$Y = 1$ iff at least two of the inputs $P,Q,R$ are $1.$
Answer: