1 votes 1 votes For the circuit shown, the counter state $\left(\mathrm{Q}_{1} \mathrm{Q}_{0}\right)$ follows the sequence $00,01,10,11,00 \ldots$ $00,01,10,00,01 \ldots$ $00,01,11,00,01 \ldots$ $00,10,11,00,10 \ldots$ Others gate2007-ec + – admin asked Sep 19, 2022 • edited Feb 24, 2023 by Lakshman Bhaiya admin 46.4k points 33 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.