GO Electronics
Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Filter
Recent
Hot!
Most votes
Most answers
Most views
Previous GATE
Featured
Recent questions
0
votes
0
answers
521
GATE ECE 1999 | Question 1.8
In the cascade amplifier shown in the given figure, if the common - emitter stage $\left(Q_{1}\right)$ has a transconductance $\mathrm{gm}_{1}$, and the common base stage $\left(Q_{2}\right)$ has a transconductance $\mathrm{gm}_{2^{\prime}}$ ... of the cascade amplifier is $g_{m 1}$ $g_{m 2}$ $\frac{g_{m 1}}{2}$ $\frac{g_{m 2}}{2}$
In the cascade amplifier shown in the given figure, if the common - emitter stage $\left(Q_{1}\right)$ has a transconductance $\mathrm{gm}_{1}$, and the common base stage...
admin
46.4k
points
94
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
522
GATE ECE 1999 | Question 1.9
Crossover distortion behaviour is characteristic of Class $\text{A}$ output stage Class $\text{B}$ output stage Class $\mathrm{AB}$ output stage Common - base output stage
Crossover distortion behaviour is characteristic ofClass $\text{A}$ output stageClass $\text{B}$ output stageClass $\mathrm{AB}$ output stageCommon - base output stage
admin
46.4k
points
108
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
523
GATE ECE 1999 | Question 1.10
The logical expresion $y=\mathrm{A}+\overline{\mathrm{A}} \mathrm{B} $ is equivalent to $y=\mathrm{AB}$ $y=\overline{\mathrm{A}} \mathrm{B}$ $y=\bar{A}+\mathrm{B}$ $y=\mathrm{A}+\mathrm{B}$
The logical expresion $y=\mathrm{A}+\overline{\mathrm{A}} \mathrm{B} $ is equivalent to$y=\mathrm{AB}$$y=\overline{\mathrm{A}} \mathrm{B}$$y=\bar{A}+\mathrm{B}$$y=\mathr...
admin
46.4k
points
105
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
524
GATE ECE 1999 | Question 1.11
A Darlington emitter - follower circuit is sometimes used in the output stage of a $\text{TTL}$ gate in order to increase its $\mathrm{I}_{\mathrm{OL}}$ reduce its $\mathrm{I}_{\mathrm{OH}}$ increase its speed of operation reduce power dissipation
A Darlington emitter - follower circuit is sometimes used in the output stage of a $\text{TTL}$ gate in order toincrease its $\mathrm{I}_{\mathrm{OL}}$reduce its $\mathrm...
admin
46.4k
points
119
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
525
GATE ECE 1999 | Question 1.12
Commercially available $\text{ECL}$ gears use two ground lines and one negative supply in order to reduce power dissipation increase fan-out reduce loading effect eliminate the effect of power line glitches or the biasing circuit
Commercially available $\text{ECL}$ gears use two ground lines and one negative supply in order toreduce power dissipationincrease fan-outreduce loading effecteliminate t...
admin
46.4k
points
115
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
526
GATE ECE 1999 | Question 1.13
The resolution of a $4$ - bit counting $\text{ADC}$ is $0.5$ volts. For an analog input of $6.6$ volts, the digital output of the $\text{ADC}$ will be $1011$ $1101$ $1100$ $1110$
The resolution of a $4$ - bit counting $\text{ADC}$ is $0.5$ volts. For an analog input of $6.6$ volts, the digital output of the $\text{ADC}$ will be$1011$$1101$$1100$$1...
admin
46.4k
points
94
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
527
GATE ECE 1999 | Question 1.14
For a second-order system with the closed-loop transfer function \[T(s)=\frac{9}{s^{2}+4 s+9}\] the settling time for $2$ - percent band, in seconds, is $1.5$ $2.0$ $3.0$ $4.0$
For a second-order system with the closed-loop transfer function\[T(s)=\frac{9}{s^{2}+4 s+9}\]the settling time for $2$ - percent band, in seconds, is$1.5$$2.0$$3.0$$4.0$...
admin
46.4k
points
117
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
528
GATE ECE 1999 | Question 1.15
The gain margin (in $d \mathrm{B}$ ) of a system a having the loop transfer function \[\mathrm{G}(s) \mathrm{H}(s)=\frac{\sqrt{2}}{s(s+1)} \text { is }\] $0$ $3$ $6$ $\infty$
The gain margin (in $d \mathrm{B}$ ) of a system a having the loop transfer function\[\mathrm{G}(s) \mathrm{H}(s)=\frac{\sqrt{2}}{s(s+1)} \text { is }\]$0$$3$$6$$\infty$
admin
46.4k
points
104
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
529
GATE ECE 1999 | Question 1.16
The system moded described by the state equations is \[ \begin{array}{l} \mathrm{X}=\left[\begin{array}{cc} 0 & 1 \\ 2 & -3 \end{array}\right] x+\left[\begin{array}{l} 0 \\ 1 \end{array}\right ... \end{array}\right] x \end{array} \] controllable and observable controllable, but not observable observable, but not controllable neither controllable nor observable
The system moded described by the state equations is\[\begin{array}{l}\mathrm{X}=\left[\begin{array}{cc}0 & 1 \\2 & -3\end{array}\right] x+\left[\begin{array}{l}0 \\1\end...
admin
46.4k
points
94
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
530
GATE ECE 1999 | Question 1.17
The phase margin (in degrees) of a system having the loop transfer function \[ \mathrm{G}(s) \mathrm{H}(s)=\frac{2 \sqrt{3}}{s(s+1)} \text { is } \] $45^{\circ}$ $-30^{\circ}$ $60^{\circ}$ $30^{\circ}$
The phase margin (in degrees) of a system having the loop transfer function\[\mathrm{G}(s) \mathrm{H}(s)=\frac{2 \sqrt{3}}{s(s+1)} \text { is }\]$45^{\circ}$$-30^{\circ}$...
admin
46.4k
points
118
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
531
GATE ECE 1999 | Question 1.18
A signal $x(t)$ has a Fourier transform $X(\omega)$. If $x(t)$ is a real and odd function of $t$, then $X(\omega)$ is a real and even function of $\omega$ a imaginary and odd function of $\omega$ an imaginary and even function of $\omega$ a real and odd function of $\omega$
A signal $x(t)$ has a Fourier transform $X(\omega)$. If $x(t)$ is a real and odd function of $t$, then $X(\omega)$ isa real and even function of $\omega$a imaginary and o...
admin
46.4k
points
61
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
532
GATE ECE 1999 | Question 1.19
The input to a channel is a bandpass signal. It is obtained by linearly modulating a sinusoidal carrier with a single-tone signal. The output of the channel due to this input is given by \[ y(t)=(1 / 100) \cos \left(100 t-10^{-6}\right) \cos \left(10^{6} t-1.56\right) \] The group ... $t_{g}=10^{8}, t_{p}=1.56 \times 10^{-6}$ $t_{g}=10^{8}, t_{p}=1.56$
The input to a channel is a bandpass signal. It is obtained by linearly modulating a sinusoidal carrier with a single-tone signal. The output of the channel due to this i...
admin
46.4k
points
136
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
533
GATE ECE 1999 | Question 1.20
A modulated signal is given by, \[ s(t)=m_{1}(t) \cos \left(2 \pi f_{c} t\right)+m_{2}(t) \sin \left(2 \pi f_{c} t\right) \] where the baseband signal $m_{1}(t)$ and $m_{2}(t)$ have bandwidths of $10 \; \mathrm{kHz}$ and $15 \; \mathrm{kHz}$, respectively. The bandwidth of the modulated signal, in $\mathrm{kHz}$, is $10$ $15$ $25$ $30$
A modulated signal is given by,\[s(t)=m_{1}(t) \cos \left(2 \pi f_{c} t\right)+m_{2}(t) \sin \left(2 \pi f_{c} t\right)\]where the baseband signal $m_{1}(t)$ and $m_{2}(t...
admin
46.4k
points
100
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
534
GATE ECE 1999 | Question 1.21
A modulated signal is given by \[s(t)=e^{-a t} \cos \left[\left(\omega_{c}+\Delta \omega\right) t\right] u(t),\] where $a, \omega_{c}$ and $\Delta \omega$ are positive constants, and $\omega_{c} \gg \Delta \omega$. The complex envelope of $s(t)$ is given by ... $\exp (j \Delta \omega t) \cdot u(t)$ $\left.\exp \left[j \omega_{c}+\Delta \omega\right) t\right]$
A modulated signal is given by\[s(t)=e^{-a t} \cos \left[\left(\omega_{c}+\Delta \omega\right) t\right] u(t),\]where $a, \omega_{c}$ and $\Delta \omega$ are positive cons...
admin
46.4k
points
105
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
535
GATE ECE 1999 | Question 1.22
An electric field on a plane is described by its potential \[\mathrm{V}=20\left(r^{-1}+r^{-2}\right)\] where $r$ is the distance from the source. The field is due to a monopole a dipole both a monopole and a dipole a quadrupole
An electric field on a plane is described by its potential\[\mathrm{V}=20\left(r^{-1}+r^{-2}\right)\]where $r$ is the distance from the source. The field is due toa monop...
admin
46.4k
points
90
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
536
GATE ECE 1999 | Question 1.23
Assuming perfect conductors of a transmission line, pure $\text{TEM}$ propagation is $\text{NOT}$ possible in coaxial cable air-filled cylindrical waveguide parallel twin-wire line in air semi-infinite parallel plate wave guide
Assuming perfect conductors of a transmission line, pure $\text{TEM}$ propagation is $\text{NOT}$ possible incoaxial cableair-filled cylindrical waveguideparallel twin-wi...
admin
46.4k
points
115
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
537
GATE ECE 1999 | Question 1.24
Indicate which one of the following will $\text{NOT}$ exist in a rectangular resonant cavity. $\mathrm{TE}_{110}$ $\mathrm{TE}_{011}$ $\mathrm{TM}_{110}$ $\mathrm{TM}_{111}$
Indicate which one of the following will $\text{NOT}$ exist in a rectangular resonant cavity.$\mathrm{TE}_{110}$$\mathrm{TE}_{011}$$\mathrm{TM}_{110}$$\mathrm{TM}_{111}$
admin
46.4k
points
48
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
538
GATE ECE 1999 | Question 1.25
Identify which one of the following will $\text{NOT}$ satisfy the wave equation. $50 \; e^{f(\omega t-3 z)}$ $\sin [\omega(10 z+5 t)]$ $\cos \left(y^{2}+5 t\right)$ $\sin (x) \cos (t)$
Identify which one of the following will $\text{NOT}$ satisfy the wave equation.$50 \; e^{f(\omega t-3 z)}$$\sin [\omega(10 z+5 t)]$$\cos \left(y^{2}+5 t\right)$$\sin (x)...
admin
46.4k
points
104
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
539
GATE ECE 1999 | Question 2.1
The Fourier series representation of an impules train denoted by \[s(t)=\sum_{n=-\infty}^{n} d\left(t-n \mathrm{~T}_{0}\right) \text { is given by }\] $\frac{1}{\mathrm{~T}_{0}} \sum_{n=-\infty}^{\infty} \exp -\frac{j 2 \pi n t}{\mathrm{~T}_{0}}$ ... $\frac{1}{\mathrm{~T}_{0}} \sum_{u=-\infty}^{\infty} \exp \frac{j 2 \pi n t}{\mathrm{~T}_{0}}$
The Fourier series representation of an impules train denoted by\[s(t)=\sum_{n=-\infty}^{n} d\left(t-n \mathrm{~T}_{0}\right) \text { is given by }\]$\frac{1}{\mathrm{~T}...
admin
46.4k
points
108
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
540
GATE ECE 1999 | Question 2.2
The Thevenin equivalent voltage $\mathrm{V}_{\mathrm{TH}}$ appearing between the terminals $A$ and $B$ of the network shown in the given figure is given by $j 16(3-j 4)$ $j 16(3+j 4)$ $16(3+j 4)$ $16(3-j 4)$
The Thevenin equivalent voltage $\mathrm{V}_{\mathrm{TH}}$ appearing between the terminals $A$ and $B$ of the network shown in the given figure is given by$j 16(3-j 4)$$j...
admin
46.4k
points
98
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
541
GATE ECE 1999 | Question 2.3
The value of $R$ (in ohms) required for maximum power transfer in the network shown in the given figure $2$ $4$ $8$ $16$
The value of $R$ (in ohms) required for maximum power transfer in the network shown in the given figure$2$$4$$8$$16$
admin
46.4k
points
66
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
542
GATE ECE 1999 | Question 2.4
A Delta-connected network with its Wye-equivalent is shown in the given figure is. The resistances $R_{1}, R_{2}$ and $R_{3}$ (in ohms) are respectively $1.5,3$ and $9$ $3,9$ and $1.5$ $9,3$ and $1.5$ $3,1.5$ and $9$
A Delta-connected network with its Wye-equivalent is shown in the given figure is. The resistances $R_{1}, R_{2}$ and $R_{3}$ (in ohms) are respectively$1.5,3$ and $9$$3,...
admin
46.4k
points
108
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
543
GATE ECE 1999 | Question 2.5
An $n$-channel $\text{JEFT}$ has $\mathrm{I}_{\mathrm{DSS}}=2 \mathrm{~mA}$ and $\mathrm{V}_{p}=-4 \mathrm{~V}$. Its transconductance $\mathrm{gm}$ (in milliohm) for an applied gate-to-source voltage $\mathrm{V}_{\mathrm{GS}}$ of $-2 \mathrm{~V}$ is $0.25$ $0.5$ $0.75$ $1.0$
An $n$-channel $\text{JEFT}$ has $\mathrm{I}_{\mathrm{DSS}}=2 \mathrm{~mA}$ and $\mathrm{V}_{p}=-4 \mathrm{~V}$. Its transconductance $\mathrm{gm}$ (in milliohm) for an a...
admin
46.4k
points
89
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
544
GATE ECE 1999 | Question 2.6
An $\text{npn}$ transistor (with $\mathrm{C}=0.3 \; \mathrm{pF}$ ) has a unity gain cutoff frequency $f_{\mathrm{T}}$ of $400 \; \mathrm{MHz}$ at a $\text{dc}$ bias current $I_{c}=1 \mathrm{~mA}$. The value of its $C_{\mu}$ (in $\mathrm{~pF}$ ) is approximately $\left(\mathrm{V}_{\mathrm{T}}=26 \; \mathrm{mV}\right)$ $15$ $30$ $50$ $96$
An $\text{npn}$ transistor (with $\mathrm{C}=0.3 \; \mathrm{pF}$ ) has a unity gain cutoff frequency $f_{\mathrm{T}}$ of $400 \; \mathrm{MHz}$ at a $\text{dc}$ bias curre...
admin
46.4k
points
52
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
545
GATE ECE 1999 | Question 2.7
An amplifier has an open-loop gain of $100$, an input impedance of $1 \; \mathrm{k \Omega}$, and an output impedance of $100 \; \Omega$. A feedback network with a feedback factor of $0.99$ is connected to the amplifier in a voltage series feedback mode. The new input and ... and $10 \; k \Omega$ $100 \; \Omega$ and $1 \; \Omega$ $100 \; k \Omega$ and $1 \; k\Omega$
An amplifier has an open-loop gain of $100$, an input impedance of $1 \; \mathrm{k \Omega}$, and an output impedance of $100 \; \Omega$. A feedback network with a feedbac...
admin
46.4k
points
54
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
546
GATE ECE 1999 | Question 2.8
A $\text{dc}$ power supply has a no-load voltage if $30 \mathrm{~V}$, and a full-load voltage of $25 \mathrm{~V}$ at a full - load current of $1 \mathrm{~A}$. Its output resistance and load regulation, respectively, are $5\; \Omega\; \mathrm{and} \;20\%$ $25 \;\Omega\; \mathrm{and} \;20 \%$ $5 \;\Omega\; \mathrm{and} \;16.7 \%$ $25\; \Omega \;\mathrm{and}\; 16.7 \%$
A $\text{dc}$ power supply has a no-load voltage if $30 \mathrm{~V}$, and a full-load voltage of $25 \mathrm{~V}$ at a full - load current of $1 \mathrm{~A}$. Its output ...
admin
46.4k
points
127
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
547
GATE ECE 1999 | Question 2.9
An amplifier is assumed to have a single-pole high-frequency transfer function. The rise time of its output response to a step function input is $35\;\text{nsec}$. The upper $-3 \; d B$ frequency (in $\text{MHz}$) for the amplifier to a sinusoidal input is approximately at $4.55$ $10$ $20$ $28.6$
An amplifier is assumed to have a single-pole high-frequency transfer function. The rise time of its output response to a step function input is $35\;\text{nsec}$. The up...
admin
46.4k
points
140
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
548
GATE ECE 1999 | Question 2.10
The minimized form of the logical expression $(\bar{A} \bar{B} \bar{C}+\bar{A} B \bar{C}+\bar{A} B C+A B \bar{C})$ is $\overline{\mathrm{A}} \overline{\mathrm{C}}+\mathrm{B} \overline{\mathrm{C}}+\overline{\mathrm{A}} \mathrm{B}$ ... $\mathrm{A} \overline{\mathrm{C}}+\overline{\mathrm{B}} \mathrm{C}+A \overline{\mathrm{B}}$
The minimized form of the logical expression $(\bar{A} \bar{B} \bar{C}+\bar{A} B \bar{C}+\bar{A} B C+A B \bar{C})$ is$\overline{\mathrm{A}} \overline{\mathrm{C}}+\mathrm{...
admin
46.4k
points
64
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
549
GATE ECE 1999 | Question 2.11
For a binary half-subtractor having two inputs $\text{A}$ and $\text{B}$, the correct set of logical expressions for the outputs $\text{D}$ ( = $\text{A}$ minus $\text{B}$ ) and $\text{X}(=$ ... $\mathrm{D}=\mathrm{AB}+\overline{\mathrm{A}} \overline{\mathrm{B}}, \mathrm{X}=\mathrm{A} \overline{\mathrm{B}}$
For a binary half-subtractor having two inputs $\text{A}$ and $\text{B}$, the correct set of logical expressions for the outputs $\text{D}$ ( = $\text{A}$ minus $\text{B}...
admin
46.4k
points
96
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
1
votes
0
answers
550
GATE ECE 1999 | Question 2.12
The ripple counter shown in the given figure is works as a $\bmod -3$ up counter $\bmod -5$ up counter $\bmod - 3$ down counter $\bmod - 5$ down counter
The ripple counter shown in the given figure is works as a$\bmod -3$ up counter$\bmod -5$ up counter$\bmod - 3$ down counter$\bmod - 5$ down counter
admin
46.4k
points
185
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
551
GATE ECE 1999 | Question 2.13
If $\text{CS}=\text{A}_{15} \; \text{ A}_{14} \; \text{A}_{13}$ is used as the chip select logic of a $4 \; \text{K RAM}$ in an $8085$ system, then its memory range will be $3000 \; \mathrm{H}-3 \; \mathrm{FFF \; H}$ ... $6000 \; \mathrm{H}-6 \; \mathrm{FFF} \; \mathrm{H} \; \text{and} \; 7000 \; \mathrm{H}-7 \; \mathrm{FFF \; H}$
If $\text{CS}=\text{A}_{15} \; \text{ A}_{14} \; \text{A}_{13}$ is used as the chip select logic of a $4 \; \text{K RAM}$ in an $8085$ system, then its memory range will ...
admin
46.4k
points
59
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
552
GATE ECE 1999 | Question 2.14
If the closed-loop transfer function $T(s)$ of a unity negative feedback system is given by \[ \mathrm{T}(\mathrm{s})=\frac{a_{n -1} \mathrm{~s}+a_{n}}{\mathrm{~s}^{n}+n_{1} s^{n-1}+\ldots+a_{n-1} s+a_{n}} \] then the steady state error for a unit ramp input is $\frac{a_{n}}{a_{n-1}}$ $\frac{a_{n}}{a_{n-2}}$ $\frac{a_{n-2}}{a_{n-2}}$ zero
If the closed-loop transfer function $T(s)$ of a unity negative feedback system is given by\[\mathrm{T}(\mathrm{s})=\frac{a_{n -1} \mathrm{~s}+a_{n}}{\mathrm{~s}^{n}+n_{1...
admin
46.4k
points
57
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
553
GATE ECE 1999 | Question 2.15
Consider the points $s_{1}=-3+j 4$ and $s_{2}=-3-j 2$ in the $s$-plane. Then, for a system with the open-loop Transfer function \[G(s) H(s)=\frac{K}{(s+1)^{4}}\] $s_{1}$ is on the root locus,but not $s_{2}$ $s_{2}$ is on the root locus, but not $s_{1}$ both $s_{1}$ and $s_{2}$ are on the root locus neither $s_{1}$ nor $s_{2}$ is on the root locus.
Consider the points $s_{1}=-3+j 4$ and $s_{2}=-3-j 2$ in the $s$-plane. Then, for a system with the open-loop Transfer function\[G(s) H(s)=\frac{K}{(s+1)^{4}}\]$s_{1}$ is...
admin
46.4k
points
101
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
554
GATE ECE 1999 | Question 2.16
For the system described by the state equation \[ x=\left[\begin{array}{ccc} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 0.5 & 1 & 2 \end{array}\right] x+\left[\begin{array}{l} 0 \\ 0 \\ 1 \end{array}\right] u \] If the control signal $u$ ... $x+v$, then the eigenvalues of the closed-loop system will be $0,-1,-2$ $0,-1,-3$ $-1,-1,-2$ $0,-1,-1$
For the system described by the state equation\[x=\left[\begin{array}{ccc}0 & 1 & 0 \\0 & 0 & 1 \\0.5 & 1 & 2\end{array}\right] x+\left[\begin{array}{l}0 \\0 \\1\end{arra...
admin
46.4k
points
42
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
555
GATE ECE 1999 | Question 2.17
The $z$-transform of a signal is given by \[C(z)=\frac{1 z^{-1}\left(1-z^{-4}\right)}{4\left(1-z^{-1}\right)^{2}}\] Its final value is $1 / 4$ zero $1.0$ infinity
The $z$-transform of a signal is given by\[C(z)=\frac{1 z^{-1}\left(1-z^{-4}\right)}{4\left(1-z^{-1}\right)^{2}}\]Its final value is$1 / 4$zero$1.0$infinity
admin
46.4k
points
35
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
556
GATE ECE 1999 | Question 2.18
The Nyquist sampling frequency (in $\mathrm{Hz}$ ) of a signal given by $6 \times 10^{4} \sin c^{2}(400 t)^{*} 10^{6} \sin c^{3}(100 t)$ is $200$ $300$ $500$ $1000$
The Nyquist sampling frequency (in $\mathrm{Hz}$ ) of a signal given by$6 \times 10^{4} \sin c^{2}(400 t)^{*} 10^{6} \sin c^{3}(100 t)$ is$200$$300$$500$$1000$
admin
46.4k
points
26
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
557
GATE ECE 1999 | Question 2.19
The peak-to-peak input to an $8$-bit $\text{PCM}$ coder is $2$ volts. The signal power-to-quantization noise power ratio (in $d\text{B}$) for an input of $0.5 \cos \left(\omega_{m} t\right)$ is $47.8$ $49.8$ $95.6$ $99.6$
The peak-to-peak input to an $8$-bit $\text{PCM}$ coder is $2$ volts. The signal power-to-quantization noise power ratio (in $d\text{B}$) for an input of $0.5 \cos \left(...
admin
46.4k
points
32
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
558
GATE ECE 1999 | Question 2.20
The input to a matched filter is given by $s(t) = \left\{\begin{matrix} 10\\ 0 \end{matrix}\right. \begin{array}{ll} \sin \left(2 \pi \times 10^{6} t\right) & 0<1<10^{-4} \mathrm{sec} \\ & \text{otherwise} \end{array}$ The peak amplitude of the filter output is $10$ volts $5$ volts $10$ millivolts $5$ millivolts
The input to a matched filter is given by$s(t) = \left\{\begin{matrix} 10\\ 0 \end{matrix}\right. \begin{array}{ll} \sin \left(2 \pi \times 10^{6} t\right) & 0<1<10^{-4} ...
admin
46.4k
points
31
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
559
GATE ECE 1999 | Question 2.21
Four independent messages have bandwidths of $100 \mathrm{~Hz}, 200 \mathrm{~Hz}$, and $400 \mathrm{~Hz}$, respectively. Each is sampled at the Nyquist rate, and the samples are time division multiplexed ($\text{TDM}$) and transmitted. The transmitted sample rate (in $\mathrm{Hz}$ ) is $1600$ $800$ $400$ $200$
Four independent messages have bandwidths of $100 \mathrm{~Hz}, 200 \mathrm{~Hz}$, and $400 \mathrm{~Hz}$, respectively. Each is sampled at the Nyquist rate, and the samp...
admin
46.4k
points
27
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
0
votes
0
answers
560
GATE ECE 1999 | Question 2.22
In a twin-wire transmission line in air, the adjacent voltage maxima are at $12.5 \mathrm{~cm}$ and $27.5 \mathrm{~cm}$. The operating frequency is $300 \; \mathrm{MHz}$ $1 \; \mathrm{GHz}$ $2 \; \mathrm{GHz}$ $6.28 \; \mathrm{GHz}$
In a twin-wire transmission line in air, the adjacent voltage maxima are at $12.5 \mathrm{~cm}$ and $27.5 \mathrm{~cm}$. The operating frequency is$300 \; \mathrm{MHz}$$1...
admin
46.4k
points
30
views
admin
asked
Sep 29, 2022
Others
gate1999-ec
+
–
Page:
« prev
1
...
11
12
13
14
15
16
17
...
79
next »
GO Electronics
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register