0 0 votes The $z$-transform of a signal is given by \[C(z)=\frac{1 z^{-1}\left(1-z^{-4}\right)}{4\left(1-z^{-1}\right)^{2}}\] Its final value is $1 / 4$ zero $1.0$ infinity Discrete-time Signals gate1999-ec discrete-time-signals z-transform numerical-answers + – admin 265 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
