0 0 votes Consider a causal second-order system with the transfer function $$G(s)=\dfrac{1}{1+2s+s^{2}}$$ with a unit-step $R(s)=\dfrac{1}{s}$ as an input. Let $C(s)$ be the corresponding output. The time taken by the system output $c(t)$ to reach $94\%$ of its steady-state value $\underset{t\rightarrow \infty}{\lim}\:c(t),$ rounded off to two decimal places, is $5.25$ $4.50$ $3.89$ $2.81$ Network Solution Methods gate2019-ec network-solution-methods transfer-function + – Arjun 714 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
