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The recursion relation to solve $x=e^{-x}$ using Newton-Raphson method is

1. $x_{n+1}=e^{-x_{n}}$
2. $x_{n+1}=x_{n}-e^{-x_{n}}$
3. $x_{n+1}=\left(1+x_{n}\right) \frac{e^{-x_{n}}}{1+e^{-x_{n}}}$
4. $x_{n+1}=\frac{x_{n}^{2}-e^{-x_{n}}\left(1+x_{n}\right)-1}{x_{n}-e^{-x_{n}}}$