Calculate the minimum value attained by the function
\[\sin (\pi x)-\sqrt{2} \pi x^{2}\]
for values of $x$ which lie in the interval $[0,1]$.
- $\frac{1}{\sqrt{2}}\left(1-\frac{\pi}{8}\right)$
- $0$
- $1-\frac{\pi}{2 \sqrt{2}}$
- $-\frac{1}{\sqrt{2}}\left(1+\frac{9 \pi}{2}\right)$
- $-\sqrt{2} \pi$