1 1 vote Let $v_1=\left[\begin{array}{l}1 \\ 2 \\ 0\end{array}\right]$ and $v_2=\left[\begin{array}{l}2 \\ 1 \\ 3\end{array}\right]$ be two vectors. The value of the coefficient $\alpha$ in the expression $v_1=\alpha v_2+e$, which minimizes the length of the error vector $e$, is$\frac{7}{2}$$\frac{-2}{7}$$\frac{2}{7}$$\frac{-7}{2}$ Linear Algebra gateece-2023 linear-algebra engineering-mathematics + – admin 1.9k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes answer c . expl: e = v1-alpha(v2) e = [1-2a,2-a,0-3a] minimizes length means orthogonal so using dot product with v2 2(1-2a)+1(2-a)+3(-3a) = 0 a = 2/7 Alex_rus01 answered Mar 4 Alex_rus01 comment Share Follow 0 reply Please log in or register to add a comment.