6 6 votes A $100 \mathrm{~cm} \times 32 \mathrm{~cm}$ rectangular sheet is folded $5$ times. Each time the sheet is folded, the long edge aligns with its opposite side. Eventually, the folded sheet is a rectangle of dimensions $100 \mathrm{~cm} \times 1 \mathrm{~cm}$. The total number of creases visible when the sheet is unfolded is ___________. $32$ $5$ $31$ $63$ Quantitative Aptitude gateece-2023 spatial-aptitude paper-folding + – admin 1.5k views answer comment Share Follow Add Sync Questions Print See 1 comment 1 1 comment reply Rohit139 commented Dec 16, 2024 i moved by Arjun May 14 reply Follow flag video solution https://www.youtube.com/watch?v=4PLOWLI_3t0&t=2s 1 1 replyShare Please log in or register to add a comment.
9 9 votes $1$ fold divides the sheet into to parts $2$ parts with $1$ crease in between. $2$ folds divides the sheet into $4$ parts with $3$ creases. $5$ folds will divides the sheet into $32$ parts with $31$ creases. Hence answer will be Option $C$ $31$ rhl answered Oct 11, 2023 • moved May 14 by Arjun rhl comment Share Follow See 1 comment 1 1 comment reply anujs commented Aug 13, 2024 i moved by Arjun May 14 reply Follow flag Alternate method:$1^{st}$ fold $\rightarrow$ $1$ new crease $= 2^{0} $$2^{nd}$ fold $\rightarrow$ $2$ new creases $= 2^{1} $$3^{rd}$ fold $\rightarrow$ $4$ new creases $= 2^{2} $$4^{th}$ fold $\rightarrow$ $8$ new creases $= 2^{3} $$5^{th}$ fold $\rightarrow$ $16$ new creases $= 2^{4} $So, total creases after $5$ folds $= 2^{0} + 2^{1} + 2^{2} + 2^{3} + 2^{4} = 2^{5} - 1 = 31$ 3 3 replyShare Please log in or register to add a comment.
0 0 votes folds crease total 1 hetalm01 answered Feb 5, 2024 hetalm01 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes fold crease total cm length 1 1 100:16 2 3 100:8 3 7 100:4 4 15 100:2 5 31 100:1 ans is c 31 hetalm01 answered Feb 5, 2024 hetalm01 comment Share Follow 0 reply Please log in or register to add a comment.