1 1 vote Consider the Earth to be a perfect sphere of radius $\text{R}$. Then the surface area of the region, enclosed by the $60^{\circ} \mathrm{N}$ latitude circle, that contains the north pole in its interior is $\_\_\_\_\_\_$. $(2-\sqrt{3}) \pi R^{2}$ $\frac{(\sqrt{2}-1) \pi R^{2}}{2}$ $\frac{2 \pi R^{2}}{3}$ $\frac{(2+\sqrt{3}) \pi R^{2}}{8 \sqrt{2}}$ Engineering Mathematics gateece-2024 engineering-mathematics geometry + – admin 2.1k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
