1 1 vote The general form of the complementary function of a differential equation is given by $y(t)=(A t+B) e^{-2 t}$, where $A$ and $B$ are real constants determined by the initial condition. The corresponding differential equation is $\frac{\mathrm{d}^{2} y}{\mathrm{~d} t^{2}}+4 \frac{\mathrm{d} y}{\mathrm{~d} t}+4 y=f(t)$ $\frac{\mathrm{d}^{2} y}{\mathrm{~d} t^{2}}+4 y=f(t)$ $\frac{\mathrm{d}^{2} y}{\mathrm{~d} t^{2}}+3 \frac{\mathrm{d} y}{\mathrm{~d} t}+2 y=f(t)$ $\frac{\mathrm{d}^{2} y}{\mathrm{~d} t^{2}}+5 \frac{\mathrm{d} y}{\mathrm{~d} t}+6 y=f(t)$ Differential Equations gateece-2024 differential-equations second-order-differential-equation engineering-mathematics + – admin 2.8k views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
0 0 votes a Rishitha K answered Jun 26, 2025 Rishitha K comment Share Follow 0 reply Please log in or register to add a comment.