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A silicon bar is doped with donor impurities $N_{D}= 2.25 \times 10^{15} \text{atoms} / cm^{3}$. Given the intrinsic carrier concentration of silicon at $T = 300 \: K$ is $n_{i}= 1.5 \times 10^{10} cm^{-3}.$ Assuming complete impurity ionization, the equilibrium electron and hole concentrations are

1. $n_{0}=1.5\times 10^{16}cm^{-3}, \: p_{0}= 1.5\times 10^{5}cm^{-3}$
2. $n_{0}=1.5\times 10^{10}cm^{-3}, \: p_{0}= 1.5\times 10^{15}cm^{-3}$
3. $n_{0}=2.25\times 10^{15}cm^{-3}, \: p_{0}= 1.5\times 10^{10}cm^{-3}$
4. $n_{0}=2.25\times 10^{15}cm^{-3}, \: p_{0}= 1\times 10^{5}cm^{-3}$