8 8 votes Operators $\square,$ $\Diamond$ and $\rightarrow$ are defined by: $a\,\square\,b=\frac{a-b}{a+b};\, a\,\Diamond\, b=\frac{a+b}{a-b};$ $a\,\rightarrow\, b=ab.$Find the value of $(66\,\square\, 6)\rightarrow(66\,\Diamond\, 6).$$-2$$-1$$1$$2$ Analytical Aptitude gate2015-ec-1 logical-reasoning easy + – Milicevic3306 712 views answer comment Share Follow Add Sync Questions Print See 1 comment 1 1 comment reply amit166 commented Oct 11, 2019 i moved by Arjun May 18 reply Follow flag independent for value of real value of a and b answer =1 1 1 replyShare Please log in or register to add a comment.
Best answer 8 8 votes $\require {cancel}(66\,\square\, 6)\rightarrow(66\,\Diamond\; 6) = \frac{\cancel{66-6}}{\cancel{66+6}} \times \frac{\cancel{66+6}}{\cancel{66-6}} = 1.$ Arjun answered Jun 1, 2019 • moved May 18 by Arjun Arjun comment Share Follow See 1 comment 1 1 comment reply Lakshman Bhaiya commented Jan 3, 2020 i moved by Arjun May 18 reply Follow flag If they asked find the value of $(P\,\square\, Q)\rightarrow(P\,\Diamond\; Q)?$ Then $(P\,\square\, Q)\rightarrow(P\,\Diamond\; Q) = \dfrac{P-Q}{P+Q} \times \dfrac{P+Q}{P-Q} = 1$ 1 1 replyShare Please log in or register to add a comment.
2 2 votes option C as (60/52)*(52/60)=1 saipriyab answered Oct 15, 2017 • moved May 18 by Arjun saipriyab comment Share Follow 0 reply Please log in or register to add a comment.