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Operators $\square,$ $\Diamond$ and $\rightarrow$ are defined by: $a\,\square\,b=\frac{a+b}{a-b};\, a\,\Diamond, b=\frac{a+b}{a-b};$ $a\,\rightarrow\, b=ab.$

Find the value of $(66\,\square\, 6)\rightarrow(66\,\Diamond, 6).$

  1. $-2$
  2. $-1$
  3. $1$
  4. $2$
in Analytical Aptitude retagged by
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