1 1 vote For $A = \begin{bmatrix} 1 &\tan x \\ -\tan x &1 \end{bmatrix},$ the determinant of $A^{T}A^{-1}$ is $\sec^{2}x$ $\cos 4x$ $1$ $0$ Linear Algebra gate2015-ec-3 linear-algebra matrices determinant + – Milicevic3306 458 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.