GATE ECE 2016 Set 1 | GA | Question: 4

Question

In a huge pile of apples and oranges, both ripe and unripe mixed together,$15\%$ are unripe fruits. Of the unripe fruits, $45 \%$ are apples. Of the ripe ones, $66 \%$ are oranges. If the pile contains a total of $5692000$ fruits, how many of them are apples?

• A. $2029198$
• B. $2467482$
• C. $2789080$
• D. $3577422$

Answer 1

Total fruits = $5692000 $

$\qquad\qquad = \begin{Bmatrix} Unripe(15\%)\rightarrow 853800 \\ Ripe(85\%)\rightarrow 4838200\end{Bmatrix}$

$= \begin{Bmatrix} Unripe(15\%)\begin{Bmatrix}Apples(45\%)\rightarrow 384210\\Orange \rightarrow Don't\ care \end{Bmatrix} \\ Ripe(85\%)\begin{Bmatrix}Apples(34\%)\rightarrow 1644988\\Orange \rightarrow Don't\ care \end{Bmatrix} \end{Bmatrix}$

So, Total Apples = 384210 + 1644988 = 2029198

Correct Answer: $A$

Answer 2

Let us consider pile contains 100%

Answer 3

Total no of unripe fruits = 5692000 × (0.15) = 853800

Total no of ripe fruits = 5692000 – 853800 = 4838200

No of unripe apples = 853800 × (0.45) = 384210

No of ripe apples = 4838200 × (0.34) = 1644988   (66% are oranges)

So, total no of apples = 384210 + 1644988 = 2029198